Answer: these regions of darkness are due to no stars being in these regions of the night sky
F_P + F_Q = M g
F_P = M g - F_Q
Torque, or moment of force:
∑ M_P = 0
∑ M_P = M g L - F_Q · 3 L
0 = M g L - 3 F_Q L / : L
0 = M g - 3 F_Q
3 F_Q = M g
F_Q = M g /3
Finally:
F_P = M g - M g/3
F_P = 4 M g / 3
Answer:
The gauge pressure is 1511.11 psi.
Explanation:
Given that,
Flow rate = 94 ft³/min
Diameter d₁=3.3 inch
Diameter d₂ = 5.2 inch
Pressure P₁= 15 psi
We need to calculate the pressure on other side
Using Bernoulli equation
We know that,
Where, V = volume
v = velocity
A = area
Put the value of v into the formula
Put the value into the formula
We need to calculate the gauge pressure
Using formula of gauge pressure
Put the value into the formula
Hence, The gauge pressure is 1511.11 psi.
One of the main contributors to the timbre of a sound is harmonics.
Ok so if each side is 4.53 cm, we can multiply 4.53 x 4.53 x 4.53 to get the volume (since v= l x w x h). Density equals mass/volume, so
519 g/4.53 cm
114.57 g/cm^3 (since none of the units cancel)