The block moves with constant velocity: for Newton's second law, this means that the resultant of the forces acting on the block is zero, because the acceleration is zero.
We are only concerned about the horizontal direction, and there are only two forces acting along this direction: the force F pushing the block and the frictional force

acting against the motion. Since their resultant must be zero, we have:

The frictional force is

where

is the coefficient of kinetic friction

is the weight of the block.
Substituting these values, we find the magnitude of the force F:
Answer:
1

2
The distance is
Explanation:
From the question we are told that
The maximum speed of the cheetah is 
The maximum of gazelle is 
The distance ahead is 
Let
denote the time which the cheetah catches the gazelle
Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

=> 
=> 
=> 
Now at t = 7.5 s

=> 
=> 
=>
Hence the for the gazelle to escape the cheetah it must be 55.2 m
Answer:
Explanation:
All matter is made up of atoms, which are turned up of protons, neutrons and electrons.
They bond together to make up matter
Answer:
see below
Explanation:
a. 0.1886 x 12
=2.2632
This has 2 sig figures so the answer can only have 2 sig figures
2.3
b. 2.995 - 0.16685
=2.82815
The most accurate in the problem is to thousands place so our answer can only be accurate to the thousands place
2.828
c. 910 x 0.18945=172.3995
The least number of significant figures is 3 so the answer can only have 3 significant figures
172
Answer:


Explanation:
Since we have given values of ω₀=32.o rad/s ,ω=0 and α=-0.700 rad/s² to find t we use below equation

To find revolutions we use below equation

Substitute the given values to find revolutions α
So

To convert rad to rev:
