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Tema [17]
1 year ago
9

19 dm expressed in millimeters

Physics
1 answer:
alina1380 [7]1 year ago
6 0
1900 millimeters thats wht i got
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. A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is orient
Dmitriy789 [7]

Answer:

The magnetic flux through surface is 2.22 \times 10^{-3} Wb

Explanation:

Given :

Magnitude of magnetic field B = 0.078 T

Radius of circle r = 0.10 m

Angle between field and surface normal \theta = 25°

From the formula of flux,

\phi = B.A

\phi = BA\cos \theta

Where \theta = angle between magnetic field line and surface normal, A = area of circular surface.

A = \pi r^{2}

A = 3.14 \times (0.10) ^{2}

A = 0.0314 m^{2}

Magnetic flux is given by,

\phi = 0.078 \times 0.0314 \times \cos 25

\phi = 2.22 \times 10^{-3} Wb

Therefore, the magnetic flux through surface is 2.22 \times 10^{-3} Wb

6 0
3 years ago
The latent heat of fusion of a substance is the amount of energy associated
kicyunya [14]

Answer:

The Answer is A Hope I helped you :D Have a Great Day!

Explanation:

6 0
3 years ago
A space expedition discovers a planetary system consisting of a massive star and several spherical planets. The planets all have
Juliette [100K]

Answer:

T/√8

Explanation:

From Kepler's law, T² ∝ R³ where T = period of planet and R = radius of planet.

For planet A, period = T and radius = 2R.

For planet B, period = T' and radius = R.

So, T²/R³ = k

So, T²/(2R)³ = T'²/R³

T'² = T²R³/(2R)³

T'² = T²/8

T' = T/√8

So, the number of hours it takes Planet B to complete one revolution around the star is T/√8

7 0
3 years ago
Which of the following is an example of pure research? Creating new elements to study their properties Producing plastics that a
koban [17]
Creating new elements in order to study their properties is definitely pure research.
It has no earthly [known] application, since the elements don't even exist, whereas
for each of the other choices, you've stated the desired application as the reason
for the search.
6 0
3 years ago
The information on a can of soda indicates that the can contains 355 mL. The mass of a full can of soda is 0.369 kg, while an em
Vilka [71]

Answer:

\rho=995.50\ kg.m^{-3}

\bar w=9765.887\ N.m^{-3}

s=0.9955

Explanation:

Given:

  • volume of liquid content in the can, v_l=0.355\ L=3.55\times 10^{-4}\ L
  • mass of filled can, m_f=0.369\ kg
  • weight of empty can, w_c=0.153\ N

<u>So, mass of the empty can:</u>

m_c=\frac{w_c}{g}

m_c=\frac{0.153}{9.81}

m_c=0.015596\ kg

<u>Hence the mass of liquid(soda):</u>

m_l=m_f-m_c

m_l=0.369-0.015596

m_l=0.3534\ kg

<u>Therefore the density of liquid soda:</u>

\rho=\frac{m_l}{v_l} (as density is given as mass per unit volume of the substance)

\rho=\frac{0.3534}{3.55\times 10^{-4}}

\rho=995.50\ kg.m^{-3}

<u>Specific weight of the liquid soda:</u>

\bar w=\frac{m_l.g}{v_l}=\rho.g

\bar w=995.5\times 9.81

\bar w=9765.887\ N.m^{-3}

Specific gravity is the density of the substance to the density of water:

s=\frac{\rho}{\rho_w}

where:

\rho_w= density of water

s=\frac{995.5}{1000}

s=0.9955

3 0
3 years ago
Read 2 more answers
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