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2 years ago

In the formula vy = ayt, what is the value of ay for an object in projectile motion?

Physics

2 answers:

Sergeu [11.5K]2 years ago

8 0

–9.8 m/s<span>2

Just took it and got it right!</span>

Deffense [45]2 years ago

6 0

Answer : The correct option is (A) $-9.8\ m/s^2$

Explanation :

The formula is given as :

$v_y=a_yt$

Where,

$v_y$ is vertical component of velocity.

$a_y$ is the vertical component of acceleration.

In a projectile motion, the particle moves in a path under the influence of gravity.

So, the vertical component of acceleration is -g i.e acceleration due to gravity.

Hence, the correct option is (a) " $a_y=-9.8\ m/s^2$ ".

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A blue car pulls away from a red stop-light just after it has turned green with a constant acceleration of 0.2 m/s2. A green car

jolli1 [7]

Answer:

After 15 seconds, the green car will catch up with the blue car

Explanation:

Let the time for the green car to catch up with the blue car be T

When the green car catches up to the blue car, the distances covered by each car after time T will be equal. Also, their velocities at that instant will be equal

Distance covered by blue car after time T is given by: s = ut + 0.5 at²

Where u = 0, a = 0.2 m/s², t = T

S = 0.5 × 0.2 × T² = 0.1 T²

Velocity of blue car, v = u+ at

v = 0.2T

Distance covered by green car at T is given as: S = Velocity × time

Where v = 0.2T, t = T - 7.5 (since the blue car started 7.5 seconds earlier)

S = 0.2T (T - 7.5)

S = 0.2 T² - 1.5T

Equating the distance covered by the two cars

0.2T² - 1.5T = 0.1T²

0.1T² - 1.5T = 0

T(0.1T - 1.5) = 0

T = 0 or

T = 1.5/0.1 = 15 secs

Therefore, after 15 seconds, the green car will catch up with the blue car

8 0

1 year ago

The vertical velocity

cestrela7 [59]

it would be at least 9.8m/s

3 0

2 years ago

Which statement is correct?

Sedbober [7]

Answer:

The answer is "Choice C ".

Explanation:

The relationship between the E and V can be defined as follows:

$\to E= -\Delta V$

Let,

$\to E= \frac{\delta V}{\delta x}$

When E=0

$\to \frac{\delta V}{\delta x}=0$

v is a constant value

Therefore, In the electric potential in a region is a constant value then the electric-field must be into zero that is everywhere in the given region, that's why in this question the "choice c" is correct.

7 0

2 years ago

El conductor de un tren que circula a 20 m/s ve un obstáculo en la vía y frena con una aceleración de 2 m/s2 hasta parar ¿cuánto

AlladinOne [14]

Velocidad inicial = 20 m/s
velocidad final = 0 m/s
aceleracion = -2 m/s^2

aceleracion = (cambio de velocidad)/(cambio de tiempo)
(cambio de tiempo)= (cambio de velocidad)/aceleracion
tiempo = (-20 m/s)/(-2 m/s^2)
= 10 segundos

x = (x(inicial)) + (v(inicial))(tiempo) + 1/2(aceleracion)(tiempo)^2
x(inicial) = 0
x = (20 m/s)(10 s) + 1/2 (-2m/s^2)(10 s)^2
x = 200 m - 100 m
x = 100 m (el espacio recorrido en los dos segundos)

espero que esto te ayude! buena suerte!

6 0

2 years ago

Technician A says test lights are great for quick tests on non-computerized circuits. Technician B says you can use a test light

Tpy6a [65]

Answer:

that technician A is right

Explanation:

The test lights are generally small bulbs that are turned on by the voltage and current flowing through the circuit in analog circuits, these two values are high and can light the bulb. In digital circuits the current is very small in the order of milliamps, so there is not enough power to turn on these lights.

From the above it is seen that technician A is right

4 0

2 years ago