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Katen [24]
3 years ago
10

In the formula vy = ayt, what is the value of ay for an object in projectile motion?

Physics
2 answers:
Sergeu [11.5K]3 years ago
8 0
–9.8 m/s<span>2

Just took it and got it right!</span>
Deffense [45]3 years ago
6 0

Answer : The correct option is (A) -9.8\ m/s^2

Explanation :

The formula is given as :

v_y=a_yt

Where,

v_y is vertical component of velocity.

a_y is the vertical component of acceleration.

In a projectile motion, the particle moves in a path under the influence of gravity.

So, the vertical component of acceleration is -g i.e acceleration due to gravity.

Hence, the correct option is (a) " a_y=-9.8\ m/s^2 ".

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Read 2 more answers
Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to
Pie

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Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x (\frac{Rc}{Rc + Ri})

where

  • Rc = resistance of copper = \frac{ρl}{a}  (l = length , a = area, ρ = resistivity of copper)
  • Ri = resistance of iron = \frac{ρ₀l}{a}  (l = length , a = area, ρ₀ = resistivity of copper)

Vc =  V x (\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}})

Vc = V x (\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})})

Vc = V x (\frac{ρ}{ρ + ρ₀})

where

  • ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
  • ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x (\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}})

Vc = 2.41 v

5 0
3 years ago
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