In the general population, one woman in eight will develop breast
1 answer:
Answer:
a) 8/10
b)
c) Independent events
Step-by-step explanation:
The given information are;
The proportion of women than carries a mutation of the BRCA gene, P(A) = 1/600
The proportion of women in which the mutation develops breast cancer, P(B) = 8/10
a) The probability that a randomly selected woman will develop breast cancer given that she has a mutation of the BRCA gene is given as follows;
1 × P(B) = 1 × 8/10 = 8/10
b) The probability, P that a randomly selected woman woman will carry the mutation of the BRCA gene and will develop breast cancer is given as follows;
P(A) × P(B) = 1/600×8/10 = 1/750 =
c) The events are dependent
Given that P(A) × P(B) = P(A∩B), the events of carrying the mutation and developing Breast cancer are independent events.
You might be interested in
Answer:
Given :
ABC is a right triangle in which ∠ABC = 90°,
Also, Legs AB and CB are extended past point B to points D and E,
Such that,
To prove :
Proof :
In triangles AEC and EBA,
∠EAC= ∠ABE ( right angles )
∠CEA = ∠AEB ( common angles )
By AA similarity postulate,
,
Similarly,
Now, In triangles ADC and CBD,
∠ACD = ∠CBD ( right angles )
∠ADC= ∠BDC ( common angles )
By AA similarity postulate,
,
Similarly,
From equations (1) and (2),
The corresponding sides of similar triangles are in same proportion,
Hence, proved....
