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Ludmilka [50]
3 years ago
15

What number is shown on the graph ?

Mathematics
1 answer:
Natalka [10]3 years ago
4 0
El numero daaaaaaaaa
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The total charge on 7 particles is −42 units. All the particles have the same charge.
icang [17]

7p = - 42

p = -42/7

p = - 6

lol

4 0
3 years ago
A customer orders a round of coffee for her friends. If she orders two 12-ounce cups and one 16-ounce cup, she will owe the coff
astra-53 [7]

Answer:

D.$3.95

Step-by-step explanation:

Let us represent

12-ounce cup = x

16-ounce cup = y

A customer orders a round of coffee for her friends.

If she orders two 12-ounce cups and one 16-ounce cup, she will owe the coffee shop $10.75.

Hence:

2x + y = 10.75.....Equation 1

y = 10.75 - 2x

If she orders one 12-ounce cup and two 16-ounce cups, she will owe the coffee shop $11.30.

Hence:

x + 2y = 11.30.....Equation 2

We substitute 10.75 -2x for y in Equation 2

x + 2(10.75 - 2x) = 11.30

x + 21.50 - 4x = 11.30

Collect like terms

x - 4x = 11.30 - 21.50

-3x = -10.20

x = -10.20/-3

x = $3.40

Solving for y

y = 10.75 - 2x

y = 10.75 - 2($3.40)

y = 10.75 - 6.8

y = $3.95

Therefore , 16-ounce cup is represented by y, the cost for a 16-ounce cup of coffee is $3.95

Option D is correct

3 0
2 years ago
What is the value of k(-3) when k(t) = -|4t|
Fantom [35]

Answer:

-12

Step-by-step explanation:

You can find the value of k(-3) by substituting t = -3 into the absolute value function k(t) = -|4t|.

k(-3) = -|4*-3| = -|-12| = -12

6 0
3 years ago
Simplify the expression. What is (-8.6)^0
blagie [28]

Answer:

1

Step-by-step explanation:

Any number to the power of zero is equal to 1. If the negative would be on the outside of the parenthesis, though, the answer would be -1

5 0
3 years ago
A construction firm bids on two different contracts. Let E1 be the event that the bid on the first contract is successful, and d
marissa [1.9K]

Calculate the probability that both bids are successful

Answer:

The probability that both contracs are successful is 0.21

Step-by-step explanation:

Given

E1 = the event that the bid on the first contract is successful

E2 = the event that the bid on the second contract is successful

P(E1) = 0.3

P(E2) = 0.7

Let P(A) represent the event that both contracts are successful

P(A) = P(E1 and E2)

Since both events are independent. P(A) becomes

P(A) = = P(E1 * P(E2)

By substituton

P(A) = 0.3 * 0.7

P(A) = 0.21

Hence the probability that both contracs are successful is 0.21

7 0
3 years ago
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