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2 years ago

The legend on a map states that

Mathematics

2 answers:

Gala2k [10]2 years ago

6 0

Answer:

3000 miles

Step-by-step explanation:

x = unknown amount of miles

1 in. = 500 miles

6 in. = x

Cross Multiply:

1x = 3000 miles

or

Normal Multiplication:

Since you know one inch is equal to 500 miles, multiply 500 by 6.

500 * 6 = 3000 miles

Gelneren [198K]2 years ago

3 0

Answer:

3000miles

Step-by-step explanation:

(┛❍ᴥ❍)┛彡┻━┻

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Help

pychu [463]

Use the following formula valid fo every polyhedron.

v-e+f=2

Search for Euler characteristic, or Euler-Poicare characteristic for more depth about this formula 

v= number of vertices

e=number of edges

f=number of faces

You get v=13

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0

2 years ago

Please solve with substitution or elimination

bezimeni [28]

11/28, -11/4 is the point form for substitution 11/28 is x and -11/4 is y

7 0

2 years ago

Read 2 more answers

School A and B are competing in an academic contest. at the beginning of the final round, school A has 174 points and school B h

zhenek [66]

Answer:

Step-by-step explanation:

First add 11 then -69

4 0

3 years ago

Read 2 more answers

The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of

kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

$A=\frac{\sqrt{3} }{4} a^{2}$

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

$A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}$

$A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}$

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

$A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}$

$A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}$

Now, comparing areas:

$\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )$

$\frac{A_{1}}{A_{2}} =$ 2.25

The area of ΔABC is 2.25x greater than the area of ΔDEF.

7 0

2 years ago

Ppppppppppllllllllls I need helppppppp

Phantasy [73]

Answer:

ΔABC≅ΔDEC by AAS

Step-by-step explanation:

You can use the AAS method of congruency.

Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent

Hope this helped.

5 0

2 years ago