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JulijaS [17]
3 years ago
7

100th number in this sequence 14 ,28 ,42 ,56

Mathematics
1 answer:
liraira [26]3 years ago
7 0
It is 1,400 Since 14x100=1,400.
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4 2/5 divided by 3 1/7 euals plz give mixed number answer ty
antoniya [11.8K]
4 2/5 = 22/5
3 1/7 = 22/7
22/5 x 7/22 = 154/110 = 7/5

The answer is 1 2/5
8 0
3 years ago
Todd's team starts a football game. On the first play, they gain 6 yards. On the second play, they lose 12 yards. The expression
Natasha2012 [34]

-6 yards

Step-by-step explanation:

6-12 = -6 yards

they lost a total of 6 yards

3 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Solve the following system of linear equation by graphing. <br>4x + 2y = -2 <br>2x – 3y = 9 ​
Viefleur [7K]
If you can graph in slope intercept, your new equations would be: y= -2x-1 and y= 2/3x-3.
Just graph those now since it should be easier.
3 0
3 years ago
Geoff has a bag that contains 4 red marbles and 6 blue marbles. He chooses two marbles at random and does not replace them. What
posledela

Total number of marbles = 10

Number of red marbles = 4

Number of blue marbles = 6

Probability = \frac{number of favorable outcomes}{total number of outcomes}

The probability that the first marble is blue = \frac{6}{10}

The probability that the first marble is red = \frac{4}{9} ; 9 because 1 marble has already been taken out.

Joint probability= probability of event A * Probability of event B

= \frac{6}{10}\times\frac{4}{9}=\frac{24}{90}= \frac{4}{15}

3 0
3 years ago
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