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2 years ago

Having trouble with this question. Can someone help me.

Mathematics

2 answers:

vodka [1.7K]2 years ago

4 0

For function one, the slope is already in mx+b form. The coefficient to x is the slope, so it is four in this case. For the second function we calculate the slope using rise over run. The rise is change in y and run is change in x, so 4/2= 2 slope. Four is greater than two so it has the greater rate of change. The answer is B

rewona [7]2 years ago

4 0

First function - y = 4x + 5
It is in the form mx + c

Slope ,m = 4

For second function
y - y1 / x - x1 = 10 - 6/ 3 -1 = 4/2 = 2
Slope = 2

So comparing them, the correct answer is B

Hope This Helps You!

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3 years ago

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3 years ago

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5 0

3 years ago

Read 2 more answers

HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH

8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

$4+\sqrt{6x}$

to get rid of the root in the denominator.

First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

$4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}$

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

$\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}$

Thank you

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2 years ago

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Dennis_Churaev [7]

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3 years ago

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