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tiny-mole [99]
3 years ago
13

A. what is asked?

Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer:

A. How much Anna weights in kilograms is what is asked (Btw is it her or his?)

B. The values given is 54000 (most likely in grams )

C. The operation that is going to be used is 1000 since kilograms is 1000 grams

D. The solution is 54 kilograms

E. To get 54 kilograms to grams we can just multiply by 1000 again which will result into 54000 thus the answer is correct

Step-by-step explanation:

A:

The question is asked when there is a "what" or a problem statement

B:

The only value or digits given is 54000

C:

in the Metric Scale Kilograms is 1000 times larger in value than grams thus 1000

D:

Divide 54000 with 1000 which is 54

E:

Um.... just multiply 1000 ._. (That's the only way I can check it)

Hope this helps!

kolbaska11 [484]3 years ago
3 0
<h3>A. What is asked?</h3>

<em>Here</em><em> </em><em>we</em><em> </em><em>are</em><em> </em><em>asked</em><em> </em><em>to</em><em> </em><em>convert</em><em> </em><em>Anna's</em><em> </em><em>weight</em><em> </em><em>from</em><em> </em><em>grams</em><em> </em><em>to</em><em> </em><em>kilograms</em><em>.</em>

<h3>B. What is the given value?</h3>

<em>The</em><em> </em><em>given</em><em> </em><em>value</em><em> </em><em>is</em><em> </em><em>her</em><em> </em><em>weight</em><em> </em><em>i.e</em><em> </em><em>54000</em><em> </em><em>grams</em><em>.</em>

<h3>C. What operations is/are being used?</h3>

<em>Here</em><em> </em><em>division</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>used</em><em> </em><em>because</em><em> </em><em>when</em><em> </em><em>we</em><em> </em><em>convert</em><em> </em><em>a</em><em> </em><em>smaller</em><em> </em><em>unit</em><em> </em><em>to</em><em> </em><em>a</em><em> </em><em>bigger</em><em> </em><em>unit</em><em> </em><em>we</em><em> </em><em>divide</em><em> </em><em>the</em><em> </em><em>mass</em><em> </em><em>value</em><em> </em><em>by</em><em> </em><em>100</em><em>0</em><em>.</em>

<h3>D. Solution:</h3>

\begin{gathered}\\ \sf\longmapsto 1\:gram=\frac{1}{1000}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 54000\:grams=\frac{54000}{1000}\end{gathered}

\begin{gathered}\\ \sf\longmapsto 54\:kg\end{gathered}

<h3>E. Check your answer:</h3>

<em>Multiply</em><em> </em><em>the</em><em> </em><em>value</em><em> </em><em>i.e</em><em> </em><em>54</em><em> </em><em>by</em><em> </em><em>100</em><em>0</em><em> </em><em>to</em><em> </em><em>check</em><em> </em><em>it</em><em>.</em>

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Answer:

x = 1

Step-by-step explanation:

Step 1: Write equation

9 - 2x = 7x

Step 2: Solve for <em>x</em>

<u>Add 2x on both sides:</u> 9 = 9x

<u>Divide both sides by 9:</u> x = 1

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

9 - 2(1) = 7(1)

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sertanlavr [38]
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labwork [276]

Answer:

<em>a)  </em>G(x)= \sin x + 2<em />

<em>b) The coordinates of P are</em>

<em />\displaystyle \left( \frac{3\pi}{2},1\right)

Step-by-step explanation:

<u>Translation</u>

The dashed line shows the graph of the function

y = \sin x

This function has a maximum value of 1, a minimum value of -1, and a center value of 0.

a)

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The value of G is

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PLEASE HELP!<br><br> Question is on photo! <br> Thank you!!
ipn [44]

We conclude that the relation presented in the picture is a function with domain: - 4 ≤ x < 1 and range: - 4 ≤ x ≤ 5. (Correct choices: B, C, H)

<h3>How to determine the domain and range of a relation and if a relation is a function</h3>

Herein we have a relation between two variables, x and y, relations involve two sets: an input set called domain and an output set called range. A relation is a function if and only if every element of the domain is related to only one element from the range.

Graphically speaking, the horizontal axis corresponds with the domain, whereas the vertical axis is for the set of the range. According to the previous concepts, we conclude that the relation presented in the picture is a function with domain: - 4 ≤ x < 1 and range: - 4 ≤ x ≤ 5. (Correct choices: B, C, H)

To learn more on functions: brainly.com/question/12431044

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Answer:

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