14 is 20% of what number <br><br> What percent of 48 is 30<br><br> Find 10% of 95<br><br> thanks

3. Jennifer writes the letters MONTANA on cards and then places the cards in a hat. What is the probability of picking a v

11111nata11111 [884]

The word Montana has a total of 7 letters this number becomes our denominator because this is the total amount of letters. Three of the letters contain vowels, this number will go on top. These letters include o, and two a (s).

This will give us the answer of 3/7. This fraction cannot be reduced any further.

The answer should result in b.

It appears the slash was forgotten to be written in the answer, try not to make this mistake on any tests!

Hope this helped! :)

8 0

3 years ago

Find the C.O.P <br> 1. (4,9) <br> 2. (4,12) <br> 3. (5,21)

artcher [175]

Answer:

fhvnnnjhnvkjfdncvjifnv

Step-by-step explanation:

5 0

2 years ago

Katie walks 1/2 mile in 1/6 hour. what is her unit rate of speed

Bond [772]

Katie travels at 0.05 mi/ min

3 0

3 years ago

Read 2 more answers

A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa

Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, the parameters are:

$z = 2.575, n = 2000, \pi = 0.77$

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942$

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0

2 years ago

1. The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag a

lapo4ka [179]

Answer:

Option d :18 bags of chips and 6 jars of salsa

Step-by-step explanation:

Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.

Inequality : $2.5x+4y\leq 60$