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gladu [14]
3 years ago
14

Determine the volume of the square pyramid below h-4 b1-6 b2-6 144 square units 36 square units 72 cubic units 48 cubic units

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer:

V = 48 cubic units

Step-by-step explanation:

V=b^{2} \frac{h}{3}         Use this equation to find the volume

V=6^{2} \frac{4}{3}         Simplify the exponent

V=36(\frac{4}{3})      Multiply

V = 48 cubic units

If this answer is correct, please make me Brainliest!

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Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

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3 years ago
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(3n+1)= 19, 22, 25, 28, 31, 34, 37,

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