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vichka [17]
4 years ago
5

How many moles of gold, a U, are in 3.60×10^-5 G of gold?

Chemistry
1 answer:
ch4aika [34]4 years ago
8 0

Answer:

See Below.

Explanation:

This is a conversion problem:

Using the molar mass of Gold (given in a periodic table) which is 196.97g/mol

you have

(3.60*10^-5 g) *\frac{1moles}{196.97g}

you always arrange the equation in a way to cancel whatever you don't want (grams) and leave what you do want (moles). Here grams cancel (top and bottom), so you're left with:

\frac{(3.60*10^-5 g) *(1)}{196.97} = 1.83*10^-7 moles of Gold

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A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

5 0
4 years ago
Use the kinetic energy equation to explain why speed has a greater impact on kinetic energy than mass.​
Lerok [7]

Answer: <em>Hopefully this helps! sorry if not. :))</em>

<em></em>

<em>Speed has a greater impact on mass because its increases in velocity have an exponentially greater impact on translational kinetic energy because kinetic energy is proportional to velocity squared. Doubling an object's mass would only double its kinetic energy, however doubling its momentum would quadruple its velocity.</em>

3 0
3 years ago
Which of the following are examples of conservable quantities? a. potential energy and length c. mechanical energy and mass b. m
Blababa [14]

Answer:

b

Explanation:

7 0
3 years ago
Given the reaction: 4A1 + 302 - 2A1,O, How many grams of Al will be
dlinn [17]

Answer:

The answer to your question is 27 g of Al

Explanation:

Data

mass of Al = ?

moles of Al₂O₃ = 0.5

The correct formula for the product is Al₂O₃

Balanced chemical reaction

               4Al + 3O₂   ⇒   2Al₂O₃

Process

1.- Calculate the molar mass of the product

Al₂O₃ = (27 x 2) + (16 x 3)

         = 54 + 48

         = 102 g

2.- Convert the moles of Al₂O₃ to grams

               102 g ---------------- 1 mol

                 x       ----------------  0.5 moles

                 x = (0.5 x 102) / 1

                 x = 51 g of Al₂O₃

3.- Use proportions to calculate the mass of Al

                4(27) g of Al --------------- 2(102) g of Al₂O₃

                     x               --------------- 51 g

                        x = (51 x 4(27)) / 2(102)

                        x = 5508 / 204

                        x = 27 g of Al

4 0
3 years ago
What is not matter in chemistry?? ​
Igoryamba

Answer:

중요하지 않은 것들의 예로는 생각, 감정, 빛, 에너지가 있습니다. ... 에너지 : 빛, 열, 운동 및 위치 에너지, 소리는 질량이 없기 때문에 물질이 아닙니다. 사물

Explanation:

Energy: Light, heat, kinetic and potential energy, and sound are non-matter because they are massless. Objects that have mass and are matter may emit energy.

5 0
3 years ago
Read 2 more answers
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