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tangare [24]
3 years ago
6

How do jet streamsinfluence the weather?

Chemistry
2 answers:
Ronch [10]3 years ago
8 0

Answer:

Jet streams act as an invisible director of the atmosphere and are largely responsible for changes in the weather across the globe. A jet stream is essentially an atmospheric highway located at the level where jets cruise. Winds in this high-speed river of air often reach 250 mph.

Explanation:

Scrat [10]3 years ago
3 0
Jet streams have slim strips of strong winds that have a huge influence on climate, as they can push air masses around and affect weather patterns.
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Ca because it has a larger atomic radius.
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A. what is atmospheric pressure?
Vanyuwa [196]

Answer:

<em>What is atmospheric pressure? -------> Atmospheric pressure is a force in an area pushed against a surface by the weight of the atmosphere of Earth, a layer of air.</em>

<em>Why does the atmosphere exert pressure? -------> Because gas particles in the air—like particles of all fluids—are constantly moving and bumping into things, so they exert pressure. </em>

<em>What is the value of atmospheric pressure at sea level, in newtons per square centimeter? -------> Atmospheric pressure at sea level is about 10 N/cm2 or 100 kPa or about 10 m of water or about 760 mm of mercury, but varies with the weather, and of course altitude.</em>

<em>I hope this helps and have a great day!</em>

Explanation:

6 0
3 years ago
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alexandr402 [8]
Both a particle and a wave?
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Calcium chloride contains only calcium and chloride, what is the formula for this compound?
shepuryov [24]
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7 0
3 years ago
For the reaction 2NH3(g) + 2O2(g)N2O(g) + 3H2O(l) H° = -683.1 kJ and S° = -365.6 J/K The standard free energy change for the rea
BlackZzzverrR [31]

Answer:

\Delta G^{0} = -457.9 kJ and reaction is product favored.

Explanation:

The given reaction is associated with 2 moles of NH_{3}

Standard free energy change of the reaction (\Delta G^{0}) is given as:

           \Delta G^{0}=\Delta H^{0}-T\Delta S^{0}   , where T represents temperature in kelvin scale

So, \Delta G^{0}=(-683.1\times 10^{3})J-(273K\times -365.6J/K)=-583291.2J

So, for the reaction of 1.57 moles of NH_{3}, \Delta G^{0}=(\frac{1.57}{2})\times -583291.2J=-457883.592J=-457.9kJ

As, \Delta G^{0} is negative therefore reaction is product favored under standard condition.

6 0
3 years ago
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