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3 years ago

Cobalt (I) fluoride how do i write this into a formula?

Chemistry

1 answer:

Nuetrik [128]3 years ago

5 0

Answer:

The answer would be CoF for Cobalt (I) Fluoride.

Explanation:

So first of all you take your periodic table and look at the valence electrons of Fluorine...it is 1. You don't need to look the valence electron of Cobalt because the "I" after Cobalt tells its valence electrons (it is a transition metal that is why). Now that Cobalt has a +1 charge and Fluorine has a -1 charge, it is automatically nuclear (means charge are cancelled out to 0). Therfore the answer is CoF.

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"The molecular formula for hydrogen sulfide is H2S. What does the formula indicate about the composition of a 1.0-gram sample of

Andru [333]

Answer:

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7 0

4 years ago

Read 2 more answers

Which of the following energy quantities is equivalent to 578 J?

svlad2 [7]

Answer:

<em>0.138 kcal</em>

Explanation:

The answer choices are:

a) 5.78 × 10⁵ kJ

b) 138 kcal

c)0.138 kcal

d)1.38 × 10⁵ kcal

<h2>Solution</h2>

You must use the conversion factors to convert J to kcal.

1cal = 4.184J

Dividing both sides by 4.184J:

⇒ 1 = 1cal/4.184J

1kcal = 1,000cal

Dividing both sides by 1,000 cal

⇒ 1 = 1kcal / 1,000 cal

Mutiply<em> 578J</em> by the conversion factors to find <em>kcal</em>:

$578J\times 1cal/4.184J\times 1kcal/1,000cal=0.138kcal$

Notice how the units J and cal cancel to yield kcal at the end.

5 0

3 years ago

All matter on earth contains energy

Dafna11 [192]

Yes; every object has energy and you cannot create or destroy energy but you can transfer it.

6 0

3 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$