Question

Which ion will most likely form a precipitate when reacted with SO42 ?

Answer 1

Answer:Ba$^2+$

Explanation:

option A:

$SO_{4}^{2-}$ is an anion and $Cl^{1-}$ is also an anion.So,there is no reaction.

option B:

$K^{+}$ reacts with $SO_{4}^{2-}$ to form $K_{2}SO_{4}$.

Since $K$ is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option C:

$Na^{+}$ reacts with $SO_{4}^{2-}$ to form $Na_{2}SO_{4}$.

Since $Na$ is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option D:

$Ba^{2+}$ reacts with $SO_{4}^{2-}$ to form $BaSO_{4}$.

Solubility of sulphates of second group elements decrease down the group.

So,$BaSO_{4}$ is a precipitate.