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deff fn [24]
3 years ago
9

Which ion will most likely form a precipitate when reacted with SO42 ?

Chemistry
1 answer:
Charra [1.4K]3 years ago
6 0
<h2>Answer:Ba^2+</h2>

Explanation:

option A:

SO_{4}^{2-} is an anion and Cl^{1-} is also an anion.So,there is no reaction.

option B:

K^{+} reacts with SO_{4}^{2-} to form K_{2}SO_{4}.

Since K is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option C:

Na^{+} reacts with SO_{4}^{2-} to form Na_{2}SO_{4}.

Since Na is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option D:

Ba^{2+} reacts with SO_{4}^{2-} to form BaSO_{4}.

Solubility of sulphates of second group elements decrease down the group.

So,BaSO_{4} is a precipitate.

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ludmilkaskok [199]

0.3268 moles of PC15 can be produced from 58.0 g of Cl₂ (and excess

P4)

<h3>How to calculate moles?</h3>

The balanced chemical equation is

P_{4}  + 10Cl_{2}  = 4PCl_{5}

The mass of clorine is m(Cl_{2}) = 58.0 g

The amount of clorine is n(Cl_{2}) = m(Cl_{2})/M(Cl_{2}) = 58/70.906 = 0.817 mol

The stoichiometric reaction,shows that

10 moles of Cl_{2} yield 4 moles of PCl_{5};

0.817 of Cl_{2} yield x moles of PCl_{5}

n(PCl_{5}) = 4*0.817/10 = 0.3268 mol

To know more about stoichiometric reaction, refer:

brainly.com/question/14935523

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