Answer:
6.88 × 10^-3mol
Explanation:
Molarity = number of moles (n) ÷ volume (V)
According to this question, there in 27.5 mL of 0.250 M KOH, the number of moles of KOH can, therefore, be calculated as follows:
number of moles = molarity × volume
Volume of KOH = 27.5mL = 27.5/1000
= 0.0275L
n = 0.0275 × 0.250
n = 0.006875 mol
n = 6.88 × 10^-3mol
Hemoglobin
The protein inside (a) red blood cells that carries oxygen to cells and carbon dioxide to the lungs is (b) hemoglobin
Answer: P = 1.37 atm
Explanation: For this problem we will use the Gay Lussac Law which is P1/T1 = P2/T2 then derive for P2 which is the outside pressure. Also remember to convert the units of temperature from °C to Kelvin.
T1 = 20°C + 273 = 293 K
T2 = -5°C + 273 = 268 K
P2 = P1 T2 / T1
= 1.50 atm ( 268 K ) / 293 K
= 1.37 atm
Cancel out the units of K so that the remaining unit will be in atm.
Answer:
1235
Explanation:
if thers a a guess in that number
4.48 mol Cl2. A reaction that produces 0.35 kg of BCl3 will use 4.48 mol of Cl2.
(a) The <em>balanced chemical equation </em>is
2B + 3Cl2 → 2BCl3
(b) Convert kilograms of BCl3 to moles of BCl3
MM: B = 10.81; Cl = 35.45; BCl3 = 117.16
Moles of BCl3 = 350 g BCl3 x (1 mol BCl3/117.16 g BCl3) = 2.987 mol BCl3
(c) Use the <em>molar ratio</em> of Cl2:BCl3 to calculate the moles of Cl2.
Moles of Cl2 = 2.987 mol BCl3 x (3 mol Cl2/2 mol BCl3) = 4.48 mol Cl2
