BRAINLIEST FOR FIRST TO HELP +20 pts

2x+y=7 NEED HELP WITH THIS EQUATION

gogolik [260]

$x=\frac{7-y}{2}$

y=7−2x

6 0

2 years ago

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NEED HELP FINDING SLOPE OF THE LINE

mamaluj [8]

Answer:

slope = - $\frac{2}{3}$

Step-by-step explanation:

calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 4, 2) and (x₂, y₂ ) = (2, - 2) ← 2 points on the line

m = $\frac{-2-2}{2-(-4)}$ = $\frac{-4}{2+4}$ = $\frac{-4}{6}$ = - $\frac{2}{3}$

5 0

1 year ago

Answer ASAP, Will give brainliest

erastova [34]

Answer:

Step-by-step explanation:

1) ABCD is a trapezium. AB ║ CD

∠ADC + ∠DAB = 180° { Co interior angles}

110° + ∠DAB = 180

∠DAB = 180 -110

∠DAB = 70°

2) Sum of all angles of trapezium = 360°

∠A + ∠B + ∠DCB + ∠D = 360

70° + 50° + ∠DCB + 110° = 360

230 + ∠DCB = 360

∠DCB = 360 - 230

∠DCB = 130°

3) For finding the height, use Pythagorean theorem

height² + base² = hypotenuse²

height² + 6² = 10²

height² + 36 =100

height² = 100 - 36

height² = 64

height = √64

height = 8 m

4) a = AB = x m

b = 9 m

h = height = 8 m

Area of trapezium = 120 m²

$\frac{(a+b)*h}{2}\\\\$ = 120

$\frac{(x+9)*8}{2} =120\\\\\\(x +9)*4 = 120$

x + 9 = 120/4

x + 9 = 30

x = 30 - 9

x = 21 m

AB = 21m

7 0

3 years ago

Darrin put the numbers 7.25, 7.52, and 5.72 and 5.27 in order from greatest to least.Is his work correct?Explain

aksik [14]

If the order of the numbers in the question are the order Darrin put theem in then no, his work is not correct. this is because 7.25 is not greater than 7.52. the real order should be 7.52,7.25, 5.72, 5.27

8 0

2 years ago

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Use the Ratio Test to determine the convergence or divergence of the series. If the Ratio Test is inconclusive, determine the co

jeka57 [31]

Answer:

<h2>A. The series CONVERGES</h2>

Step-by-step explanation:

If $\sum a_n$ is a series, for the series to converge/diverge according to ratio test, the following conditions must be met.

$\lim_{n \to \infty} |\frac{a_n_+_1}{a_n}| = \rho$

If $\rho$ < 1, the series converges absolutely

If $\rho > 1$ , the series diverges

If $\rho = 1$ , the test fails.

Given the series $\sum\left\ {\infty} \atop {1} \right \frac{n^2}{5^n}$

To test for convergence or divergence using ratio test, we will use the condition above.

$a_n = \frac{n^2}{5^n} \\a_n_+_1 = \frac{(n+1)^2}{5^{n+1}}$

$\frac{a_n_+_1}{a_n} = \frac{{\frac{(n+1)^2}{5^{n+1}}}}{\frac{n^2}{5^n} }\\\\ \frac{a_n_+_1}{a_n} = {{\frac{(n+1)^2}{5^{n+1}} * \frac{5^n}{n^2}\$

$\frac{a_n_+_1}{a_n} = {{\frac{(n^2+2n+1)}{5^n*5^1}} * \frac{5^n}{n^2}\\$

aₙ₊₁/aₙ =

$\lim_{n \to \infty} |\frac{ n^2+2n+1}{5n^2}| \\\\Dividing\ through\ by \ n^2\\\\\lim_{n \to \infty} |\frac{ n^2/n^2+2n/n^2+1/n^2}{5n^2/n^2}|\\\\\lim_{n \to \infty} |\frac{1+2/n+1/n^2}{5}|\\\\$

note that any constant dividing infinity is equal to zero

$|\frac{1+2/\infty+1/\infty^2}{5}|\\\\$

$\frac{1+0+0}{5}\\ = 1/5$

$\rho = 1/5$

Since The limit of the sequence given is less than 1, hence the series converges.

5 0

2 years ago