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Lemur [1.5K]
3 years ago
13

GUYSSSS!!!! PLS HELP ME! how to find integer solutions of an equation!!! STEP BY STEP!!!! PLS I DON'T UNDERSTAND!!!!!

Mathematics
1 answer:
Oksanka [162]3 years ago
6 0
To add: add the absolute values of the integers
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Solve. Enter your answer as a mixed number. The driving distance from Alex's house to the museum is 6 9 10 miles. What is the ro
givi [52]

Answer:

13.8 miles

Step-by-step explanation:

The driving distance from Alex's house to the museum is 6\frac{9}{10} miles

Since the distance from his house to the museum does not change, his trip back is also 6\frac{9}{10} miles.

The Round-Trip Distance is the distance to and from the museum.

To determine this, there ate two approaches.

  1. Add the distances together
  2. Multiply the distance to by 2.

Approach 1

6\frac{9}{10}+6\frac{9}{10}\\\\=\frac{69}{10} + \frac{69}{10} \\=\frac{69+69}{10}\\=\frac{138}{10}\\=13\frac{4}{5}=13.8

Approach 2

6\frac{9}{10} X 2 \\=\frac{69}{10} X 2\\=\frac{69X2}{10}\\=\frac{138}{10}\\=13.8 miles

The round trip distance is 13.8 miles.

5 0
3 years ago
Read 2 more answers
Karen buys a bottle of water for $1.79. She gives the cashier a $5 bill. How much should she get back
Volgvan

Answer:

3.21

Step-by-step explanation:

.........................

7 0
3 years ago
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A 222-inch pipe is cut into two pieces. One piece is five times the length of the other. Find the length of the shorter piece.
viktelen [127]

Answer:

The shorter piece is <u>37</u> inches long.

Step-by-step explanation:

Let the length of the shorter piece be x and the longer piece be 5x.

Short piece + Long piece = 222 inches

x + 5x = 222

6x = 222

x = 222 ÷ 6

x = 37

5 0
3 years ago
Suppose two dice are tossed and the numbers on the upper faces are observed. let s denote the set of all possible pairs that can
aleksandr82 [10.1K]

Suppose two dice are tossed and the numbers on the upper faces are observed. let s denote the set of all possible pairs that can be observed.

Answer: If two dice are tossed, there are 6^{2} =36 possible outcomes.The possible pairs that can be observed are given in a set denoted by s below:

\left[\begin{array}{cccccc}(1,1)&(1,2)&(1,3)&(1,4)&(1,5)&(1,6)\\(2,1)&(2,2)&(2,3)&(2,4)&(2,5)&(2,6)\\(3,1)&(3,2)&(3,3)&(3,4)&(3,5)&(3,6)\\(4,1)&(4,2)&(4,3)&(4,4)&(4,5)&(4,6)\\(5,1)&(5,2)&(5,3)&(5,4)&(5,5)&(5,6)\\(6,1)&(6,2)&(6,3)&(6,4)&(6,5)&(6,6)\end{array}\right]

5 0
3 years ago
What percent is equivalent to Two-thirds?
Talja [164]
To find the answer, divide.
2/3≈0.66666667
We know that 1/3 is .333333..., so .666666 is 2.3. To convert to a percent, we multiply by 100.
66.66666%
We can convert this .66666 back into 2/3.
66 2/3%
Therefore, our answer is
= 66 2/3%
I hope this helps!
5 0
3 years ago
Read 2 more answers
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