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11111nata11111 [884]
2 years ago
13

Solve the inequality7y + 2 < 5y + 12​

Mathematics
1 answer:
prisoha [69]2 years ago
7 0

Answer:

y < 5

Step-by-step explanation:

7y + 2 < 5y + 12

-2                   -2

7y < 5y + 10

-5y         -5y

2y < 10

/2      /2

y < 5

Hope this helps :)

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Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
  • Perpendicular = \sqrt{Hypotenuse^2 - Base^2}

<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

∴ x = 30m

3 0
3 years ago
Patrica scored 80% on a math test. She missed 4 problems. How many problems were on the test?
svet-max [94.6K]

Answer:

20

Step-by-step explanation:

Patrica got 80% correct.  She missed 4 problems, so that must have been the remaining 20% of the test.

Therefore:

4 = 20% x

Percent means out of 100, so:

4 = (20/100) x

4 = 1/5 x

x = 20

There were 20 problems on the test.

3 0
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iren2701 [21]

Answer:

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Step-by-step explanation:

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a = 14

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nth term = a + (n - 1) d

n(78) = 14 + (78 - 1) * -9

= 14 + 77(-9)

= 14 -693

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2 years ago
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12 divided by -3 is what?
Mamont248 [21]
-4 because when you did use 12 divided by 3 you get four but this is negative so you get a negative answer
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2 years ago
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Setler79 [48]

Answer: Its A

Step-by-step explanation:

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