M∠C = m∠F, There are different additional facts that would guarantee the triangles are similar. One is if you are told that the length of AB is twice the length of DE. Another is if angle C is congruent to angle F. You only need one of the two facts above. Are you given choices?
6 points would be the unit rate for one question.
The answer is 10110
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Explanation:
Divide 22 over 2. Use long division to find the quotient and remainder
22/2 = 11 remainder 0 <<--- this remainder will be used later. Call it A, so A = 0
Now repeat for the value 11, which was the quotient above
11/2 = 5 remainder 1 <<--- this remainder will be used later. Call it B, so B = 1
Repeat again for the quotient we just got
5/2 = 2 remainder 1 <<--- this remainder will be used later. Call it C, so C = 1
Repeat again
2/2 = 1 remainder 0 <<--- this remainder will be used later. Call it D, so D = 0
Repeat again
1/2 = 0 remainder 1 <<--- this remainder will be used later. Call it E, so E = 1
The last quotient above is 0, so we stop here. If we tried to keep going, then we'd get nothing but 0 remainders forever.
The remainders we got above were:
A = 0
B = 1
C = 1
D = 0
E = 1
The idea is to read the remainders in reverse order in which we found. So we start with E and work back to A
E = 1
D = 0
C = 1
B = 1
A = 0
So 22 base 10 = 10110 base 2
Answer:
2/54 3/81 4/108 5/135
I think.
Step-by-step explanation:
The hare's final displacement is given by the Pythagorean theorem as
√((13 m)² + (4 m)²) ≈ 13.601 m
The time it took to get there was (31 min)*(60 s/min) = 1860 seconds.
The direction was arctan(4/13) ≈ 17.1° north of east.
The hare's average velocity was (13.601 m)/(1860 s) on a bearing of 72.9°.
0.00731 m/s ∠72.9°
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Velocity is a vector quantity having both speed and direction. Here, we choose to express the direction as a bearing measured clockwise from North.