When CaF₂ dissolves, it dissociates as follows; CaF₂ --> Ca²⁺ + 2F⁻ If molar solubility of CaF₂ is x, then molar solubility of Ca²⁺ is x and F⁻ is 2x. ksp is solubility product constant and it can be calculated as follows; ksp = [Ca²⁺][F⁻]² ksp = (x)(2x)² ksp = 4x³ 4x³ = 1.5 x 10⁻¹⁰ x³ = 0.375 x 10⁻¹⁰ x = 3.3 x 10⁻⁴ M To calculate solubility in terms of g/L, we have to know the molar mass of CaF₂. Solubility of CaF₂ is 3.3 x 10⁻⁴ mol/L x 78 g/mol = 0.0257 g/L
Explanation: The law of superposition states that in a sequence of rock layers, the youngest layer is on the top, and the oldest one is on the bottom, each being younger than the one beneath it and older than the one above it.