Volume of sphere = ![\frac{4}{3}\pi r^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20r%5E%7B3%7D)
where,
= ![3.14](https://tex.z-dn.net/?f=3.14)
r = radius of sphere
Put the given value of volume in above formula i.e. (
)
Thus,
![1.9\times 10^{-30}m^{3} = \frac{4}{3}\3.14 r^{3}](https://tex.z-dn.net/?f=1.9%5Ctimes%2010%5E%7B-30%7Dm%5E%7B3%7D%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5C3.14%20r%5E%7B3%7D)
![1.9\times 10^{-30}m^{3} = 4.1867 r^{3}](https://tex.z-dn.net/?f=1.9%5Ctimes%2010%5E%7B-30%7Dm%5E%7B3%7D%20%3D%204.1867%20r%5E%7B3%7D)
![r^{3} = \frac{1.9\times 10^{-30}m^{3}}{4.1867}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%3D%20%5Cfrac%7B1.9%5Ctimes%2010%5E%7B-30%7Dm%5E%7B3%7D%7D%7B4.1867%7D)
![r^{3} = 0.453\times 10^{-30}m^{3}](https://tex.z-dn.net/?f=r%5E%7B3%7D%20%3D%200.453%5Ctimes%2010%5E%7B-30%7Dm%5E%7B3%7D)
![r = \sqrt[3]{0.453\times 10^{-30}m^{3}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B0.453%5Ctimes%2010%5E%7B-30%7Dm%5E%7B3%7D%7D)
= ![0.768\times 10^{-10}m](https://tex.z-dn.net/?f=0.768%5Ctimes%2010%5E%7B-10%7Dm)
= ![7.68\times 10^{-12}m](https://tex.z-dn.net/?f=7.68%5Ctimes%2010%5E%7B-12%7Dm)
= ![7.68 picometers](https://tex.z-dn.net/?f=7.68%20picometers)
Thus, radius of the carbon atom is ![7.68 picometers](https://tex.z-dn.net/?f=7.68%20picometers)
The answer is D because one of them is sharing their electrons with the other.
An ion is an atom with a different number of electrons than its number of proton, the charge of an ion is not net
need more information to find the charge but it can't be 0 if it is an ion
an ionic bond is when 2 or more ions attract negative and positive