You would find mostly grasses and nonwoody plants in a savanna.
Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Solution : Given,
Volume of solution = 500 ml
Molarity of KOH solution = 0.189 M
Molar mass of KOH = 56 g/mole
Formula used :

Now put all the given values in this formula, we get the mass of solute KOH.


Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Answer:
I Would bc it's the better opportunity
The composition would be more "diluted" in a sense.
Answer:
They Are all O's/oberavtions, because inference is using facts and reasoning, which is not the case here.
Explanation: