Answer: Mean = 7.8
Median = 9
Mode = 2,9
Step-by-step explanation: <u>Mean</u> is the average value of a data set. Mean from a frequency table is calculated as:

E(X) = 7.8
Mean for the given frequency distribtuion is 7.8.
<u>Median</u> is the central term of a set of numbers. Median in a frequency table is calculated as:
1) Find total number, n:
n = 10 + 9 + 10 + 7 + 3 + 4 + 3 = 46
2) Find position, using: 
= 23.5
Median is in the 23.5th position.
3) Find the position by adding frequencies: for this frequency distribution, 23.5th position is 9
Median for this frequency distribution is 9.
<u>Mode</u> is the number or value associated with the highest frequency.
In this frequency distribution, 2 and 9 points happen 10 times. So, mode is 2 and 9.
Mode for this distribution is 2 and 9.
I need help my self lol XD
Answer:

Step-by-step explanation:
-This is an LCM problem.
-To simplify, we introduce a least common multiplier which is equivalent the product of the denominators:

#We introduce the LCM and adjust the fractions based on it :

Hence, the simplified form of the fraction is: 
If you want to solve this problem using formulas, there are two important formulas:
t1 = first term = -5
tn = nth term = last term = -5
n = numbr of terms
Sn = sum of the n terms
tn = t1 + (n - 1)d ---> 65 = -5 + (n - 1)(5)
65 = -5 + 5n - 5
65 = -10 + 5n
75 = 5n
n = 15
Sn = n(t1 + tn)/2 ---> Sn = 15(-5 + 65)/2
Sn = 450
So ur answer rounds up to 450
Letter c
:)
hope i helped
~Luis