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Irina-Kira [14]
3 years ago
11

Thanks for the help...

Mathematics
1 answer:
AveGali [126]3 years ago
6 0
36% of the students in the sample prefer cats.
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Distance= 2797.2 time= 0.15 speed
Nutka1998 [239]
Speed = Distance ÷ Time

Distance = 2797.2

Time = 0.15

2797.2 / 0.15 = 18,648

Speed = 18,648
7 0
3 years ago
Read 2 more answers
sweaters that are regularly sell for 36 dollars and on sale for 30 percent off how much is the discount
Liula [17]

Answer:

Step-by-step explanation: 36-30%= 25.2

your answer should be 25.2

7 0
2 years ago
6/8 time is twice as fast as 3/4<br> True or False
vovangra [49]

Answer:

true

Step-by-step explanation:

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4 0
3 years ago
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A manufacturer finds that the revenue generated by selling x units of a certain commodity is given by the function R(x) = 60x −
bonufazy [111]
R(x) = 60x - 0.2x^2

The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150

Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
7 0
3 years ago
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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
3 years ago
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