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2 years ago

4(x−1)−3(2x−5) plz help

2 answers:

6 0

First you distribute. 4 to x-1 and 3 times 2x-5 you should get 4x-4-6x+15 because -3 times -5 is positive 15. Combine like terms 6x-4x is 2x and 15-4 is 11

professor190 [17]2 years ago

6 0

Answer:

11-2x

Step-by-step explanation:

4(x-1)-3(2x-5)

Open the brackets

4x-4-6x+15

Collect like terms

4x-6x-4+15

11-2x

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Sadiq measured the dimensions of a 1 kg bag of sugar and found the length was 9.2 cm, the width was 6 cm and the height was 14.1

garik1379 [7]

Answer:

$d=1.28\times 10^{-6}\ g/cm^3$

Step-by-step explanation:

The mass of a bag of sugar, m = 1 kg = 0.001 g

Length of bag, l = 9.2 cm

Width of bag, b = 6 cm

Height of the bag, h = 14.1 cm

We need to find the density of the sugar bag.

Density = mass/volume

So,

$d=\dfrac{0.001\ g}{9.2\times 6\times 14.1\ cm^3}\\\\d=1.28\times 10^{-6}\ g/cm^3$

So, the density of the bag is $1.28\times 10^{-6}\ g/cm^3$ .

7 0

2 years ago

Find the value of x.

svetoff [14.1K]

Answer:

x=17 plz the brainliest!

Step-by-step explanation:

3x+39=90

3x+39-39=90-39

3x=51

\frac{3x}{3}=\frac{51}{3}

x=17

3 0

3 years ago

What is the length of side a? Round to the nearest tenth of an inch. <br><br> Please and thank youuu

lord [1]

Answer:

using Pythagoras rule, 16^2 -7^2 =a^2

so 256-49 = 297.

√207 =14.38 to the nearest tenth of an inch is 14inch.which is your answer

6 0

2 years ago

What is the area of the composite figure

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

To find the area of a composite figure, separate it into the regular parts which make the irregular shape. This shape is composed of a semi-circle and a rectangle. Find the area by finding the area of each shape.

Semi-circle:

The semi-circle has a diameter of 2 + 4 + 2 = 8. The area this figure uses the radius which is half the diameter. The radius is 4. To find the area substitute r = 4 into $\pi r^2 = \pi 4^2 = 16\pi$ . However the semi-circle has a smaller circle cut out of it with radius 2. The area of the smaller circle is $\pir^2 = \pi 2^2=4\pi$ . The semi circle in the shape is the areas subtracted which equals 12π.