Solution:
The standard equation of a hyperbola is expressed as
Given that the hyperbola has its foci at (0,-15) and (0, 15), this implies that the hyperbola is parallel to the y-axis.
Thus, the equation will be expressed in the form:
The asymptote of n hyperbola is expressed as
Given that the asymptotes are
This implies that
To evaluate the value of h and k,
Look at the attachment!
Thanks. (I can’t see the Tuesday 24 Question 5, sorry.)
Use Multiplication Distribute Property: (xy)^a = x^ay^a
6^2(x^-2)^2(0.5x)^4
Simplify 6^2 to 36
36(x^-2)^2(0.5x)^4
Use this rule: (x^a)^b = x^ab
36x^-4(0.5x)^4
Use the Negative Power Rule: x^-a = 1/x^a
36 × 1/x^4(0.5x)^4
Use the Multiplication Distributive Property: (xy)^a = x^ay^a
36 × 1/x^4 × 0.5^4x^4
Simplify 0.5^4 to 0.0625
36 × 1/x^4 × 0.0625x^4
Simplify
2.25x^4/x^4
Cancel x^4
<u>2.25</u>
