One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:

And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees

Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
Answer:
<h3>35</h3><h3 />
Step-by-step explanation:
see attached image.
perimeter of trapezoid = sides (6 + 8 + 5 + 8 + 8)
= 35
Answer:
-21
Step-by-step explanation:
It would have to be -21 because there's -7, but the threes not negative so it would have to be -21
10x10=100 that the answer
Y = kx, so y/x is constant
you want y such that
y/12 = -2/-8