Suppose 46% of the students in a university are baseball players. If a sample of 622 students is selected, what is the probabili ty that the sample proportion of baseball players will be greater than 47%? Round your answer to four decimal places.
2 answers:
Answer:
Well by looking at this proportion the answer might be 1.0217
Step-by-step explanation:
46% of 622 = 286.12
47% of 622 = 292.34
292.34 / 286.12 = 0.0217...
Answer:
Probability of proportion will greater than 47% = 0.6915
Step-by-step explanation:
Given data:
population proportion p = 0.46
sample proportion b
sample size be n = 622
Probability of proportion will greater than 47%
= P(z >0.500)
from standard z table
= 0.6915
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