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aleksandrvk [35]
2 years ago
7

Suppose 46% of the students in a university are baseball players. If a sample of 622 students is selected, what is the probabili

ty that the sample proportion of baseball players will be greater than 47%? Round your answer to four decimal places.
Mathematics
2 answers:
Nesterboy [21]2 years ago
5 0

Answer:

Well by looking at this proportion the answer might be 1.0217

Step-by-step explanation:

46% of 622 = 286.12

47% of 622 = 292.34

292.34 / 286.12 = 0.0217...

Naya [18.7K]2 years ago
4 0

Answer:

Probability of proportion will greater than 47% = 0.6915

Step-by-step explanation:

Given data:

population proportion p = 0.46

sample proportion b \hat p = 0.47

sample size be n = 622

Probability of proportion will greater than 47%

P(\hat p > 0.47) = P[\fraca{\hat p - p}{\sqrt{p(1-p)/n}}]

= P[z > {\frac{0.47 -0.46}{\sqrt{0.46(1-0.46)/622}}]

                          = P(z >0.500)

from standard z table

= 0.6915

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Hope this helps!

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Answer:

1. y = 11

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Step-by-step explanation:

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