<span>There are 4 long rows and 5 short rows in the theater. x represents the number of chairs in each long row and y represents the number of chairs in each short row.
So, total number of chairs in 4 long rows= 4x
Total number of chairs in 5 short rows = 5y
Total number of chairs in the theater on a normal day = 4x + 5y
When 2 chairs are added to each long row, the number of chairs will change to (x+2).
So, total number of chairs in 4 long rows will be = 4(x+2)
When 3 chairs are added to each short row, the number of chairs will change to (y+3)
So, total number of chairs in 5 short rows will be = 5(y+3)
Thus, total number of chairs in the theater in rush day = 4(x+2) + 5(y+3)
= 4x + 8 + 5y + 15
= 4x + 5y + 23
Thus we can say the number of chairs increase by 23 as compared to a normal day.
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Answer:
tkae j ad by f then subtracr the u then add the c then multply k then say u
Step-by-step explanation:
The complete factorisation of 50a²b⁵ − 35a⁴b³ + 5a³b⁴ is 5a²b³(10b² - 7a² + ab)
<h3>How to factorise?</h3>
Factorisation is the process of writing an expression as a product of two or more common factors.
The expression is written as a product of several factor.
Therefore,
50a²b⁵ − 35a⁴b³ + 5a³b⁴
Hence, the complete factorisation is as follows;
5a²b³(10b² - 7a² + ab)
learn more on factorisation here: brainly.com/question/2272501
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