Answer:
A. y+8=2(x-4)
Step-by-step explanation:
A line perpendicular to y=-1/2x+11 would have slope +2, which is the negative reciprocal of -1/2.
Starting with the slope-intercept form of the equation of a straight line, find the y-intercept based upon this new line's passing through (4, -8):
y = mx + b becomes -8 = 2(4) + b. Then b = -16, and the desired new line is
y = 2x - 16.
Eliminate answer choices B and C, because 1/2 is not the correct slope.
Choice A is correct. Note that the result of subbing 4 for x and -8 for y into A: y + 8 = 2(x - 4) is a true equation: -8 + 8 = 2(4 - 4)
Also note that y + 8 = 2(x - 4) can be written in slope-intercept form:
y = -8 + 2x - 8, or y = 2x - 16 (same as obtained earlier)
Answer:
∠A and ∠C are vertical and equal in measure
∠C is adjacent to the angle that is 27°
∠C and ∠B are supplementary
∠A and ∠B are supplementary AND adjacent
All of them are correct
Step-by-step explanation:
<u><em>This is just how to find the angles.</em></u>
"When two lines intersect they form two pairs of opposite angles, A + C and B + D. Another word for opposite angles are vertical angles. Vertical angles are always congruent, which means that they are equal. Adjacent angles are angles that come out of the same vertex." - MathPlanet
The 27° and the 90° angles added up equal ∠B
∠B = 117°
360°-117°-117°=∠A & ∠C
∠A + ∠C = 126°
∠A=∠C=63°
Answer
No
Step-by-step explanation:
Since you 4x3=12 3x3 = 9
Answer:
y = -
x - 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (5, - 4) and (x₂, y₂ ) = (0, - 1) ← 2 points on the line
m =
=
= - 
Note the line crosses the y- axis at (0, - 1) ⇒ c = - 1
y = -
x - 1 ← equation in slope- intercept form
Say we add 5 to each element. We sum them up and divide by the number of elements (compute mean). Well we added 5n to that total sum and are dividing by n. So if the mean was 10 before, now it’s 15. (We had 10 datapoints added too 100, but we added 50, dividing by 10 we get 15).
Now every single data point is just as close to the mean as it was before. The mean shifted with 5, but so did the datapoints. Remember, variance is the sum of squared errors divided by n, or n-1 for sample. Well, the sum of squared errors did not change. So our estimate of variance remains the same as well as our estimate of standard deviation.
This is without assuming normality. (ie through the equation of mean and standard deviation themselves). In general expected values shift with constants, and variances remain stable.