Answer:

Step-by-step explanation:

Cos(Angle) = Adjacent leg / Hypotenuse
Cos(X) = 3.5/4.6
X = arccos(3.5/4.6)
X = 40.46 degrees.
Answer:
The probability is 1/41664.
To calculate the probability, write a fraction. The numerator is the number of ways the outcome can occur. The denominator is the number of different outcomes.
Thus, 1 is the number of outcomes we want. 41664 is the total number of different combinations possible.
Answer:
We accept H₀. We do not have argument to keep the claim that the mean breaking strength has increased
Step-by-step explanation:
Normal Distribution
Population Mean μ₀ = 1850 pounds
Standard Deviation σ = 90 pounds
Type of test
Null Hypothesis H₀ ⇒ μ = μ₀
Alternative Hypothesis Hₐ ⇒ μ > μ₀
A one tail test (right)
n = 21 as n < 30 we use t-student table
degree of fredom 20
t = 2.845
Sample mean μ = 1893
Then, we compute t statistics
t(s) = [ 1893 - 1850 ] / 90/ √n
t(s) = 43 * 4,583 / 90
t(s) = 197,069 / 90
t(s) = 2,190
And we compare t and t(s)
t(s) = 2.190
t = 2.845
Then t(s) < t
We are in the acceptance zone, we accept H₀
30/35 = 6/7
8/40 = 1/5
15/20 = 3/4
This would help :))