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IrinaK [193]
2 years ago
9

An element's atomic number is 25. How many protons would an atom of this element have?

Physics
1 answer:
s344n2d4d5 [400]2 years ago
7 0
An element's "Atomic number" IS the number of protons
in the nucleus of each atom of the element.

If an element's Atomic number is 25, then it must follow ...
as the night follows the day ... that each atom of this element
has 25 protons in its nucleus.  If it has a different number of
protons in its nucleus, then it's an atom of a different element.
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Determine the velocity that a car should have while traveling around a frictionless curve of radius 100m and that is banked 20 d
alex41 [277]

Answer:

v=18.89\frac{m}{s}

Explanation:

From the free-body diagram for the car, we have that the normal force has a vertical component and a horizontal component, and this component act as the centripetal force on the car:

\sum F_x:Nsin(20^\circ)=ma_c(1)\\\sum F_y:Ncos(20^\circ)=mg(2)

Solving N from (2) and replacing in (1):

N=\frac{mg}{cos(20^\circ)}\\(\frac{mg}{cos(20^\circ)})sin(20^\circ)=ma_c\\gtan(20^\circ)=a_c

The centripetal acceleration is given by:

a_c=\frac{v^2}{r}

Replacing and solving for v:

gtan(20^\circ)=\frac{v^2}{r}\\v=\sqrt{grtan(20^\circ)}\\v=\sqrt{9.8\frac{m}{s^2}(100m)tan(20^\circ)}\\v=18.89\frac{m}{s}

4 0
3 years ago
How do you think density plays a role in the atmosphere?
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Answer:
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Step By Step Explanation:
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Describe what happens to the KE of the simple pendulum as it swings back and forth.
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Two cylindrical containers are placed on a turntable. canister A is empty; canister B contains lead shots. each canister is the
devlian [24]

Answer:

c) both containers slide off the turntable at the same turntable speed.

Explanation:

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3 years ago
A parallel plate capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is conne
sergiy2304 [10]

Answer:

C) Both the charge on the plates of the capacitor and its capacitance would change.

Explanation:

The capacitance of parallel plate capacitor without dielectric material is given as;

C = \epsilon_o\frac{A}{d}

A parallel plate capacitor with a dielectric between its plates has a capacitance given by;

C = K \epsilon_o\frac{A}{d}

where;

C is the capacitance

K is the dielectric constant

ε₀ is permittivity of free space

A is the area of the plates

d is the distance of separation of the two plates

  • first point to note, is that the capacitance increases when dielectric material is inserted by a factor 'k'

Again, Q = CV    (without dielectric material)

Q = C_KV   (with dielectric material)

  • second point to note, is that charge stored in the plates increases due to presence of dielectric material.

Finally, we can conclude that both the charge on the plates of the capacitor and its capacitance would change.

8 0
3 years ago
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