1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KengaRu [80]
3 years ago
9

At present most of the world's energy needs are supplied by what kind of energy

Physics
1 answer:
antiseptic1488 [7]3 years ago
4 0

Fossil fuels . . . coal, oil, natural gas

Among primitive cultures, wood is an important source.
You might be interested in
What causes competition among organisms?
dimaraw [331]
Both organisms attempt to use the same limited sources
5 0
3 years ago
Suppose that a planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average o
Musya8 [376]

Explanation:

It is given that,

A planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury.

Mass of the Sun, M=1.99\times 10^{30}\ kg

Radius of Mercury's orbit, r=5.79\times 10^{10}\ m

Radius of discovered planet, R=\dfrac{2}{3}r

R=\dfrac{2}{3}\times 5.79\times 10^{10}\ m=3.86\times 10^{10}\ m

Let T is the orbital period of such a planet. Using Kepler's third law of planetary motion as :

T^2\propto R^3

T^2=\dfrac{4\pi^2R^3}{GM}

T^2=\dfrac{4\pi^2\times (3.86\times 10^{10})^3}{6.67\times 10^{-11}\times 1.99\times 10^{30}}

T=\sqrt{1.71\times 10^{13}}

T = 4135214.625 s

or

T = 47.86 days

So, the orbital period of such a planet is 47.86 days. Hence, this is the required solution.

6 0
3 years ago
Help me please, need more assistance
Dmitrij [34]

Explanation:

12) q = mCΔT

125,600 J = (500 g) (4.184 J/g/K) (T − 22°C)

T = 82.0°C

13) Solving for ΔT:

ΔT = q / (mC)

a) ΔT = 1 kJ / (0.4 kg × 0.45 kJ/kg/K) = 5.56°C

b) ΔT = 2 kJ / (0.4 kg × 0.45 kJ/kg/K) = 11.1°C

c) ΔT = 2 kJ / (0.8 kg × 0.45 kJ/kg/K) = 5.56°C

d) ΔT = 1 kJ / (0.4 kg × 0.90 kJ/kg/K) = 2.78°C

e) ΔT = 2 kJ / (0.4 kg × 0.90 kJ/kg/K) = 5.56°C

f) ΔT = 2 kJ / (0.8 kg × 0.90 kJ/kg/K) = 2.78°C

14) q = mCΔT

q = (2000 mL × 1 g/mL) (4.184 J/g/K) (80°C − 20°C)

q = 502,000 J

20) q = mCΔT

q = (2000 g) (4.184 J/g/K) (100°C − 15°C) + (400 g) (0.9 J/g/K) (100°C − 15°C)

q = 742,000 J

24) q = mCΔT

q = (0.10 g) (0.14 J/g/K) (8.5°C − 15°C)

q = -0.091 J

6 0
3 years ago
You could use an analytical or triple beam balance to determine a ___ called ____
GaryK [48]

Answer:

a and b are the correct answers

Explanation:

7 0
3 years ago
Read 2 more answers
One end of a string 4.32 m long is moved up and down with simple harmonic motion at a frequency of 75 Hz . The waves reach the o
max2010maxim [7]

To solve this problem, we will apply the concepts related to the kinematic equations of linear motion, which define speed as the distance traveled per unit of time. Subsequently, the wavelength is defined as the speed of a body at the rate of change of its frequency. Our values are given as,

\text{Length of the string} = L = 4.32 m

\text{Frequency of the wave} = f = 75 Hz

\text{Time taken to reach the other end} = t = 0.5 s

Velocity of the wave,

V = \frac{L}{t}

V = \frac{4.32 m}{0.5s}

V = 8.64m/s

Wavelength of the wave,

\lambda = \frac{V}{f}

\lambda = \frac{8.64m/s}{75Hz}

\lambda = 0.1152m

\lambda = 11.52cm

Therefore the wavelength of the waves on the string is 11.53 cm

4 0
3 years ago
Read 2 more answers
Other questions:
  • How many milliliters are in 3.65L
    14·2 answers
  • A 60.0 kg girl stands up on a stationary floating raft and decides to go into shore. She dives off the 180 kg floating raft with
    6·1 answer
  • The prefix kilo- means
    14·2 answers
  • What is the acceleration of this object? The object's mass is 60 kg.
    13·2 answers
  • A quickly moving van and a slowly moving bird have a head-on collision. The bird splatters all over the windshield as a result.
    13·1 answer
  • A photon of wavelength 15 x 10^-12 m hits an electron at rest, causing the electron to move. The photon bounces off the electron
    9·1 answer
  • Which is an example of velocity?
    14·2 answers
  • Does air defy gravity?
    15·1 answer
  • A light rope is attached to a block with mass 3.60 kg that rests on a frictionless, horizontal surface. The horizontal rope pass
    15·1 answer
  • What is needed to start a chemical reaction
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!