What is the key difference between mechanical and electromagnetic waves

Instructions Write a program that inputs the length of two pieces of fabric in feet and inches (as whole numbers) and prints the

diamong [38]

Answer:

The code is written in python in the explanation section below

Explanation:

a_feet = int(input("Input the feet of the first fabric: "))

a_inches = int(input("input the size in inches for the first piece of fabric: "))

b_feet = int(input("input the size in Feet for the second piece of fabric: "))

b_inches = int(input("Enter the size in Inches for the second piece of fabric: "))

sum_inches = a_inches + b_inches

inches_to_feet = sum_inches // 12

rem_from_div = sum_inches % 12

sum_feet = a_feet + b_feet + inches_to_feet

print("Feet: {} Inches: {}".format(sum_feet, rem_from_div))

4 0

3 years ago

E) Thermal energy is released during

vichka [17]

Answer:

e) True, f) False

Explanation:

e) Let consider a close system, that is, a system with no mass interactions with surroundings. Then, we get the following expression by the First Law of Thermodynamics:

$Q_{net,in} - W_{net, out} = \Delta U$ (1)

Where:

$Q_{net, in}$ - Net input heat, measured in joules.

$W_{net, out}$ - Net output work, measured in joules.

$\Delta U$ - Change in thermal energy, measured in joules.

Please notice that work comprises all kind of work (i.e. mechanical, electric, magnetic), whereas heat comprises all heat interactions including chemical and radioactive phenomena.

If thermal energy is released, then $\Delta U < 0$ , which is caused by three scenarios:

(i) $Q_{net,in} < 0$ , $W_{net, out} < 0$ , $|Q_{net,in}|>|W_{net,out}|$

(ii) $Q_{net, in} > 0$ , $W_{net,out} > 0$ , $|Q_{net,in}|$

(iii) $Q_{net,in}< 0$ , $W_{net, out}>0$

In the case $Q_{net,in} > 0$ , $W_{net, out}$ , the thermal energy of the system is increased. Therefore, thermal energy is released during some energy conversions. Answer: True

f) A liquid solidifies when temperature goes below point of fusion, meaning a realease of heat with no work interactions. That is:

$Q_{net, in} = \Delta U$ , $Q_{net, in} < 0$ (2)

If $Q_{net, in} < 0$ , then $\Delta U < 0$ . Then, if a liquid absorbs heat energy, then thermal energy is increase and the liquid does not solidifies. Answer: False.

7 0

3 years ago

Explain why the moon is always half illuminated and half dark no matter where it is in the lunar cycle.

BlackZzzverrR [31]

The easiest way I know to explain it is this:

-- Take a flashlight and a ball into a dark room.

-- Turn on the flashlight and point it at the ball.

-- Half of the ball is lighted up by the flashlight, and the other half is dark.

-- There is no way you can turn or twist the ball to make more or less
than 50% of it lighted up and more or less than 50% of it dark.

<em>Everything</em> in the solar system ... as long as it's shaped like a ball ... is
half illuminated by the sun and half dark.

7 0

3 years ago

All objects emit what radiation

Eduardwww [97]

If an object is not at Absolute Zero, then it is
absorbing and radiating thermal (heat) energy.

5 0

3 years ago

An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in

riadik2000 [5.3K]

Answer:

B) with 9/10 submerged

Explanation:

$m$ = mass of ice cube

$\rho$ = density of soft drink

$V$ = Volume of soft drink displaced

ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write

weight of ice cube = weight of soft drink displaced

$mg = \rho V g$

$m = \rho V$

we see that the acceleration due to gravity cancel out both side and hence it does affect as astronaut is on earth on in a lunar module.

8 0

3 years ago

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