Answer:
The mass of unknown object is 8.62Kg
Explanation:
To develop this problem it is necessary to apply the equations related to the Drag force and the Force of Gravity.
For the given point, that is, the moment at which the terminal velocity is reached, the two forces equalize, that is,
By definition we know that the Drag force is defined as
Where,
Drag coefficient
Density
A =Cross-sectional Area
V = Velocity
In the other hand we have,
Where,
Mass of sphere
Mass of unknown object
Equating the two equations we have to
Re-arrange for m_2,
Our values are given by,
Replacing in the equation we have,
<em>Therefore the mass of unknown object is 8.62Kg</em>
Answer:
Explanation:
<u>Net Force</u>
Newton's second law explains the dynamics principles when a number of forces are applied to an object.
The net force vector is the sum of the individual vector forces applied. The magnitude of the net force is related to the magnitude of the acceleration of the body as follows:
Furthermore, the acceleration can be calculated if we know the kinematic behavior of the body:
Where vf, vo, and t are the final speed, initial speed, and time, respectively.
The box is pushed across the floor with a force of 25 N against a frictional force of 14 N.
The net force applied to the box is:
We also know the box is accelerated from rest (vo=0) to vf=4 m/s in t=16 seconds, thus:
From the equation:
We solve for m:
Answer:
4.022 seconds and 4.99 seconds
Explanation:
Hello!
The free fall of the stone corresponds to a uniformly varied rectilinear movement
d=V_0*t+1/2*g*t^2
Being a free fall the initial speed is zero.
The distance is positive when considered in the same direction and direction as acceleration and speed.
256 feet stone
79.25 m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2
t = 4.022 seconds
400 feet stone
121.92m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2
t= 4,99 seconds
success with your homework!
Answer:
Prob. D
Explanation:
I am also a Visual Learner.
Answer:
I think so is b kinetic o a potential
