Answer:
Yes there is if number of bulb is high the bulbs wouldn't glow much brighter
Explanation:
Answer:
the radius of the earth in himalayan region is greater than terai reagion. therefore, the value of 'g' at the poles is greater than the value of g at the equator. 12
Explanation:
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The conclusion that is best supported by the data is;
D) A1 and B1 are like poles, but there is not enough information to tell whether they are north poles or south poles.
Answer:
0.003034 s
1.035 m
4.5 m
Explanation:
= frequency of the tone = 329.6 Hz
= Time period of the sound wave
we know that, Time period and frequency are related as
= speed of the sound in the air = 341 ms⁻¹
wavelength of the sound is given as
= speed of the sound in the water = 1480 ms⁻¹
wavelength of the sound in water is given as
The concept of this problem is the Law of Conservation of Momentum. Momentum is the product of mass and velocity. To obey the law, the momentum before and after collision should be equal:
m₁ v₁ + m₂v₂ = m₁v₁' + m₂v₂', where
m₁ and m₂ are the masses of the proton and the carbon nucleus, respectively,
v₁ and v₂ are the velocities of the proton and the carbon nucleus before collision, respectively,
v₁' and v₂' are the velocities of the proton and the carbon nucleus after collision, respectively,
m(164) + 12m(0) = mv₁' + 12mv₂'
164 = v₁' + 12v₂' --> equation 1
The second equation is the coefficient of restitution, e, which is equal to 1 for perfect collision. The equation is
(v₂' - v₁')/(v₁ - v₂) = 1
(v₂' - v₁')/(164 - 0) = 1
v₂' - v₁'=164 ---> equation 2
Solving equations 1 and 2 simultaneously, v₁' = -138.77 m/s and v₂' = +25.23 m/s. This means that after the collision, the proton bounced to the left at 138.77 m/s, while the stationary carbon nucleus move to the right at 25.23 m/s.
