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DaniilM [7]
3 years ago
11

As you drive in your car at 22.5 mi/h, you see a child’s ball roll into the street ahead of you. You hit the brakes and stop as

quickly as you can. In this case, you come to rest in 2 s. How far does your car travel as you brake to a stop? (Use: 1 mile= 1600 m, 1 h= 3600s)
Physics
1 answer:
evablogger [386]3 years ago
5 0

Answer:

Explanation:

Speed of car =22.5miles/hr

U=22.5miles/hour

Applied brake and come to rest

Final velocity, =0

t, =2sec

Given that,

Speed=distance /time

Then,

Distance, =speed, ×time

Converting mile/hour to m/s

Given that

Use: 1 mile= 1600 m, 1 h= 3600s

22.5miles/hour × 1600m/mile × 1hour/3600s

Therefore, 22.5mile/hour=10m/s

Using speed =10m/s

Distance =speed ×time

Distance=10×2

Distance, =20m

The distance travelled before coming to rest is 20m.

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The unit measurement for sound can be expressed in terms of intensity and in decibels. The intensity of sound is the measure of its power over unit area. The common unit of measurement is in decibels. This is commonly used in measuring the extent of noise. The conversion from intensity to the decibel unit is through logarithmic function. The formula is:

dB = 10 log(I/I0), where I0 is 10^-12 Watts per square meter

Substituting the values to the equation,

84 = 10log(I/10^-12)
I = 0.0002512 W/m2

In scientific notation the intensity is 2.512 x 10^-4 W/m^2.
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4 years ago
How much heat is required to raise 100 grams of water (c= 4.18) by 5 degrees Celsius?
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Answer:

Heat capacity, Q = 2090 Joules.

Explanation:

Given the following data;

Mass = 100 grams

Specific heat capacity = 4.18 J/g°C.

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To find the quantity of heat required;

Heat capacity is given by the formula;

Q = mct

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature of an object.

Substituting into the formula, we have;

Q = 100*4.18*5

Heat capacity, Q = 2090 Joules.

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Two capacitors are connected in series and the combination is charged to 120V. There's 90.0V across one capacitor, whose capacit
IgorC [24]

Answer:

0.84μF

Explanation:

Charge is same through both the capacitors since they are in series. Total voltage is the sum of the voltages of the individual capacitors.. So voltage across the 2nd capacitor is 120- 90 =30 V.

Charge across first capacitor is Q = C₁V₁ = 90 x0.28 = 25.2μC

Therefore capacitance of 2nd capacitor =

C₂ = Q÷V₂ = 25.2÷30 = 0.84 μF

                                                     

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