Which of the following functions are continuously the interval 0<x<2?

Help me with my math quiz from friday 4/1 SHOW STEPS

malfutka [58]

Hie!! I will be solving the questions in the sequence of the attachments.

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4. As line SU and TV are intersecting each other at O.

A.T.Q, ∠UOV = (7x - 4)°

∠SOT = 87°

Then, ∠UOV = ∠SOT {Vertically Opposite Angles}

$\rightarrow\sf{7x - 4=87}$

$\rightarrow\sf{7x =87+4}$

$\rightarrow\sf{7x =91}$

$\rightarrow\sf{x =\frac{91}{7}}$

$\rightarrow\boxed{\bf{x =13}}$

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5. radius = 17ft

circumference of circle = 2πr

$\rightarrow\sf{circumference=2\times\frac{22}{7}\times17}$

$\rightarrow\boxed{\bf{circumference=106.8ft}}$

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3. ∠1 and ∠2 - add to 180 (linear pair)

∠1 and ∠3 - equal (Vertically Opposite Angles)

∠3 and ∠4 - add to 180 (linear pair)

∠2 and ∠4 - equal (Vertically Opposite Angles)

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2. 160° + (6x - 16)° = 180° (linear pair)

$\rightarrow\sf{6x - 16 = 180-160}$

$\rightarrow\sf{6x - 16 = 20}$

$\rightarrow\sf{6x = 20+16}$

$\rightarrow\sf{6x =36}$

$\rightarrow\sf{x =\frac{36}{6}}$

$\rightarrow\boxed{\bf{x =6}}$

8 0

2 years ago

I'll give u brianliest if you share the answer and how you got it

Bogdan [553]

Answer:a is 52 b is 65

Step-by-step explanation:

a:Write 65% as 65100.

65100 of 80 = 65100 × 80.

Therefore, the answer is 52. If you are using a calculator, simply enter 65÷100×80 which will give you 52 as the answer.

b: it is 65 because it is the same question but in reverse which still gives you the same answer.

Hope this helps

please give brainlyist

6 0

3 years ago

Read 2 more answers

Oil is leaking out of a ruptured tanker at the rate of r(t)=30e^(?0.09t) thousand liters per minute.

zmey [24]

Answer:

A)

At t = 0, oil is leaking out of a ruptured tanker at the rate of 30 thousand liters per minute.

At t = 60, oil is leaking out of a ruptured tanker at the rate of 0.1355 thousand liters per minute.

B)

331.82 thousands of liters leak out during the first hour.

Step-by-step explanation:

The oil leakage rate, in thousand liters per minute, is:

$r(t) = 30e^{-0.09t}$

A. At what rate, in thousands of liters per minute, is the oil leaking out

At t = 0:

This is r(0)

$r(t) = 30e^{-0.09t}$

$r(0) = 30e^{-0.09*0} = 30$

At t = 0, oil is leaking out of a ruptured tanker at the rate of 30 thousand liters per minute.

At t = 60:

This is r(60)

$r(t) = 30e^{-0.09t}$

$r(60) = 30e^{-0.09*60} = 0.1355$

At t = 60, oil is leaking out of a ruptured tanker at the rate of 0.1355 thousand liters per minute.

B. How many thousands of liters leak out during the first hour?

r(t) is in thousand liters per minute.

Each hour has 60 minutes.

So the answer to this question is the integral from 0 to 60 of r(t).

Integral of the exponential function

$\int {e^{at}} \, dt = \frac{e^{at}}{a}$

So

$\int\limits^{60}_0 {r(t)} \, dt$

$\int\limits^{60}_0 {30e^{-0.09t}} \, dt$

$-333.33e^{-0.09t}$ , from t = 0 to t = 60.

This is

$-333.33e^{-0.09*60} - (-333.33e^{-0.09*0}) = 331.82$

331.82 thousands of liters leak out during the first hour.

6 0

4 years ago

Explain how you can use an array to find partial products and the product for 6*36

Klio2033 [76]

U can put hearts in a row 36 in each 6 groups
♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥♥
that 6 times

6 0

4 years ago

Solve s=m/4(a+h) for h

Pavlova-9 [17]

Answer:

h = (m/4 - as)/s

Step-by-step explanation:

s = m / 4(a+h)

(a+h) · s = m/4 >multiplied (a+h) on both side

as + hs = m/4 >distributed the s to (a+h)

hs = m/4 - as >subtracted as on both side

h = (m/4 - as)/s >divided s on both side

4 0

4 years ago