The point has to be validated I believe
The answer to this question is: C) Meteor Shower
Two parallel plates having charges of equal magnitude but opposite sign are separated by 11.0 cm. Each plate has a surface charge density of 49.0 nC/m2. A proton is released from rest at the positive plate.
(a) Determine the magnitude of the electric field between the plates from the charge density.
b) Determine the potential difference between the plates.
Answer:
a
The Electric Field between the two plate is
b
The potential difference between the plate is V =
Explanation:
From the we are given that
The separation between the plate is
The surface charge density is
Generally Electric field between the plate is mathematically given as
Note that is the permitivity of free space and its value is
Now substituting values we have
Generally Potential difference between the plate is mathematically given as
Where E is the electric field which is
Substituting value we have
V =
I would say a because i just had this