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masya89 [10]
4 years ago
13

How does the work required to stretch a spring 2 cm compare with the work required to stretch it 1 cm

Physics
1 answer:
LuckyWell [14K]4 years ago
3 0

Answer:

The work done required is W_{1}=4W_{2}

Explanation:

Given that,

Stretch spring = 2 cm

Stretch spring = 1 cm

We need to calculate the work done

Using formula of work done

W_{1}=\dfrac{1}{2}kx_{1}^2

Put the value into the formula

W_{1}=\dfrac{1}{2}\timesk\times0.02^2.....(I)

We need to calculate the work done

Using formula of work done

W_{2}=\dfrac{1}{2}kx_{2}^2

Put the value into the formula

W_{1}=\dfrac{1}{2}\timesk\times0.01^2.....(II)

We need to calculate the work done

Using equation (I) and (II)

\dfrac{W_{1}}{W_{2}}=\dfrac{\dfrac{1}{2}\timesk\times0.02^2}{\dfrac{1}{2}\timesk\times0.01^2}

\dfrac{W_{1}}{W_{2}}=\dfrac{0.02^2}{0.01^2}

W_{1}=4W_{2}

Hence, The work done required is W_{1}=4W_{2}

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The correctly balanced equation for H2O2 → H2O + O2 is
Citrus2011 [14]

Answer:2H2O2 → 2H2O + O2

Explanation:

For a chemical equation to be balanced, the number of moles of each element at the reactant must be equal to that of the product.

According to the equation given

H2O2 → H2O + O2

There are two hydrogen atoms with two oxygen atoms at the reactant and 2hydrogen and 3oxygen at the product which shows the equation is not balanced. To balance this,

We will add 2 moles to H2O2 at the reactant and 2 moles to H2O at the product to give;

2H2O2 → 2H2O + O2 (Balanced equation)

As we can see that we now have 4 moles of Hydrogen and 4 moles of oxygen at both reactant and product making the equation balanced.

8 0
3 years ago
Which of the following is an example of work?
EastWind [94]

Answer:

it's D

Explanation:

6 0
3 years ago
In a given neuron, the current membrane potential is 60 mv. what does this tell you about the current potential compared to the
alekssr [168]

The membrane is depolarized compared to the resting membrane potential.

Through conformational changes from closed, nonconducting states to an open, current-conducting state, membrane depolarization activates sodium channels. Na+ channels open slowly and change from an open state to a nonconducting, rapidly inactivated state as a result of delayed openings, which contribute to the declining fraction of INa induced by prolonged depolarization. Additionally, sodium channels can move swiftly from the closed state to the fast-inactivated state. When the membrane is depolarized, inactivated channels are prevented from opening.

The distribution of channels between the closed and slow-inactivated states, however, limits the number of excitable sodium channels as a function of the membrane potential since slow inactivation acts at greater negative potentials than fast inactivation.

To learn more about membrane potential please visit-
brainly.com/question/8438145
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3 0
2 years ago
What type of stretch is responsible for squeezing rock?
Lera25 [3.4K]
<span>Compressional stress</span>
3 0
3 years ago
A child on a playground swings through a total of 32°. If the displacement is equal on each side of the equilibrium position, wh
sashaice [31]
Let L = length of the swing.

Let the lowest position of the swing be the reference point.
Therefore in the lowest position,
The height of the swing = 0,
The support for the swing is at height = L.

At 32° swing relative to the vertical,
The height of the swing is
A = L - Lcos(32°) = L[1 - cos(32°)] = 0.152L

Answer:
The amplitude is 0.152*L, where L = length of the swing.
6 0
4 years ago
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