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3 years ago

Calculate the net force of the object in the image shown 20N 15 N

Physics

1 answer:

zmey [24]3 years ago

6 0

It’s going to be 35 bc it’s going the same way so it’s gonna be 35n

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Across what potential difference does an electron have to be accelerated in order to reach the speed v=3e7 m/s?

zmey [24]

When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation

here by energy conservation we can say that

change in kinetic energy of electron = electrostatic potential energy gained through given potential difference

kinetic energy is given as

$KE = \frac{1}{2}mv^2$

electrostatic potential energy is given as

$PE = qV$

now by energy conservation

$qV = \frac{1}{2}mv^2$

given that for electron

$m = 9.1 * 10^{-31} kg$

$v = 3 * 10^7 m/s$

$q = 1.6 * 10^{-19} C$

now by plug in values

$1.6 * 10^{-19} * V = \frac{1}{2}*9.1* 10^{-31} *(3*10^7)^2$

$V = \frac{4.095 * 10^{-16}}{1.6 * 10^{-19}}$

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4 0

3 years ago

a steam engine works on its vicinity and 285k heat is released with the help of 225C energy absorbed to the system. what is the

Sedaia [141]

Explanation:

define the term specific heat capacity of water

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3 years ago

A silver bar with a mass of 250.0 g is heated from 22.0°C to 68.5°C. How much heat does the silver bar absorb?

Harrizon [31]

Answer:

Q = 2790 J

Explanation:

Mass of silver bar is 250 g

It is heated from 22.0°C to 68.5°C

The specific heat of silver is 0.240 J/g°C

It is required to find the heat absorb by the silver bar. The heat absorbed by an object when heated from one temperature to another is given by :

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GDP deflator =Nominal GDP/Real GDP ×(100/1)

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4 years ago

A 0.140 m high cylinder is filled with mercury(density=13600 kg/m^3). what is the pressure at the bottom of the cylinder?(unit=P

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Answer:18678.24pa or 0.184atm

Explanation: P= density *height *acceleration due to gravity

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gravity =9.81m/s^2

H=0.140m

Pressure =13600*9.81*0.140

Pressure =18678.24pa or 0.184atm

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3 years ago

Calculate the net force of the object in the image shown 20N 15 N ​

Calculate the net force of the object in the image shown 20N 15 N