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3 years ago

The correctly balanced equation for H2O2 → H2O + O2 is

Physics

1 answer:

Citrus2011 [14]3 years ago

8 0

Answer:2H2O2 → 2H2O + O2

Explanation:

For a chemical equation to be balanced, the number of moles of each element at the reactant must be equal to that of the product.

According to the equation given

H2O2 → H2O + O2

There are two hydrogen atoms with two oxygen atoms at the reactant and 2hydrogen and 3oxygen at the product which shows the equation is not balanced. To balance this,

We will add 2 moles to H2O2 at the reactant and 2 moles to H2O at the product to give;

2H2O2 → 2H2O + O2 (Balanced equation)

As we can see that we now have 4 moles of Hydrogen and 4 moles of oxygen at both reactant and product making the equation balanced.

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Fluids can flow and change shape to fit their containers. Which two states are fluids?

mr_godi [17]

Answer: the two states that are fluid are;-

#{1} liquid

#{2} gas

Explanation:

as we know that there are mainly three states of substance

but among them only two of them can fluid and takes the shape of the container that are liquid and gas

4 0

3 years ago

Calculate the power provided by a 12 volt car battery with a rating of 350 amperes.

mamaluj [8]

Answer:

Option D

4200 W

Explanation:

Power, P is also given as the product of voltage and current, expressed as P=VI

Here, P is power, V is voltage in the xircuit and I is current theough voltage.

Taking 12 V for voltage across and 350A for current across circuit then power will be

P=350*12=4200 W

Therefore, option D is correct.

8 0

3 years ago

A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a complete circle of radius R. The centra

Dmitriy789 [7]

Answer:

(a). If z = 0, The electric field due to the rod is zero.

(b). If z = ∞, The electric field due to the rod is $E\propto\dfrac{1}{z^2}$ .

(c). The positive distance is $\dfrac{R}{\sqrt{2}}$

(d). The maximum magnitude of electric field is $1.54\times10^{4}\ N/C$

Explanation:

Given that,

Radius = 2.00 cm

Charge = 4.00 mC

(a). If the radius and charge are R and Q.

We need to calculate the electric field due to the rod

Using formula of electric field

$E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{Qz}{(z^2+R^2)^{\frac{2}{3}}}$

Where, Q = charge

z = distance

If z = 0,

Then, The electric field is

$E=0$

(b). If z = ∞, z>>R

So, R = 0

Then, the electric field is

$E=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{Q}{z^2}$

$E\propto\dfrac{1}{z^2}$

(c). In terms of R,

We need to calculate the positive distance

If $E\rightarrow E_{max}$

Then, $\dfrac{dE}{dz}=0$

$\dfrac{Q}{4\pi\epsilon_{0}}(\dfrac{(z^2+R^2)^\frac{3}{2}-\dfrac{3z}{2}(z^2+R^2)^\dfrac{1}{2}}{(z^2+R^2)^2})=0$

Taking only positive distance

$z=\dfrac{R}{\sqrt{2}}$

(d). If R = 2.00 and Q = 4.00 mC

We need to calculate the maximum magnitude of electric field

Using formula of electric field

$E_{max}=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{Qz}{(z^2+R^2)^{\frac{2}{3}}}$

$E_{max}=9\times10^{9}\times\dfrac{4.0\times10^{-6}\times\dfrac{2.00}{\sqrt{2}}}{((\dfrac{2.00}{\sqrt{2}})^2+(2.00)^2)^{\frac{2}{3}}}$

$E_{max}=15418.7\ N/C$

$E_{max}=1.54\times10^{4}\ N/C$

Hence, (a). If z = 0, The electric field due to the rod is zero.

(b). If z = ∞, The electric field due to the rod is $E\propto\dfrac{1}{z^2}$ .

(c). The positive distance is $\dfrac{R}{\sqrt{2}}$

(d). The maximum magnitude of electric field is $1.54\times10^{4}\ N/C$

6 0

3 years ago

What are the folds called inside the mitochondria?

max2010maxim [7]

The inner membrane has many overlapping folds called cristae. Inside the inner membrane there is the mitochondrial matrix, it contains enzymes that are used in creating ATP.
You're welcome. :)

7 0

3 years ago

Read 2 more answers

7. If a person starts from a standstill and the person can accelerate at 1 m/s/s, how long will it take for the person to get up

uranmaximum [27]

Use the first kinematic formula
Vf = Vi + at
10 = 0 + 1(t)
10 = t

10 seconds

6 0

3 years ago