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sertanlavr [38]
3 years ago
10

The correctly balanced equation for H2O2 → H2O + O2 is

Physics
1 answer:
Citrus2011 [14]3 years ago
8 0

Answer:2H2O2 → 2H2O + O2

Explanation:

For a chemical equation to be balanced, the number of moles of each element at the reactant must be equal to that of the product.

According to the equation given

H2O2 → H2O + O2

There are two hydrogen atoms with two oxygen atoms at the reactant and 2hydrogen and 3oxygen at the product which shows the equation is not balanced. To balance this,

We will add 2 moles to H2O2 at the reactant and 2 moles to H2O at the product to give;

2H2O2 → 2H2O + O2 (Balanced equation)

As we can see that we now have 4 moles of Hydrogen and 4 moles of oxygen at both reactant and product making the equation balanced.

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tangare [24]

Answer:

net exporter

Explanation:

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2 years ago
To make ice, a freezer that is a reverse Carnot engine extracts 37 kJ as heat at -17°C during each cycle, with coefficient of pe
Dvinal [7]

Answer:

a) 6.4 kJ

b) 43.4 kJ

Explanation:

a)

Q_{a} = Heat absorbed = 37 kJ

β  = Coefficient of performance = 5.8

W = Work done

Heat absorbed is given as

Q_{a} = β W

37 = (5.8) W

W = 6.4 kJ

b)

Q  = work per cycle required

Q  = Q_{a} + W

Q  = 37 + 6.4

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3 years ago
A wire with resistance R is connected to the terminals of a 6.0 V battery. What is the potential difference between the ends of
Bas_tet [7]

Answer:

Potential difference = 6.0 V

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I for 3.0Ω = 2 A

Explanation:

Potential difference (ΔV) = Current (I) x Resistance (R)

The potential difference is constant and equals 6.0 V, hence;

I = ΔV/R

When R = 1.0, I =6/1 = 6 amperes

When R = 2.0, I = 6/2 = 3 amperes

When R = 3.0, I = 6/3 = 2 amperes

<em>The potential difference is 6.0 V and the current is 6, 3, and 2 amperes for a resistance of 1.0, 2.0 and 3.0Ω respectively.</em>

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3 years ago
The charge that passes a cross-sectional area A=10-4 m2 varies with time according
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Answer:

Current = dQ/dt

or I = dQ/dt

Where I represents current.

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At time t=2sec

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S=5m
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3 years ago
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