Answer:
v= 300 m/s
Explanation:
Given that
altitude ,h= 4500 m
The mass ,m = 3 kg
Lets take acceleration due to gravity , g= 10 m/s²
The speed before impact at sea level = v
Initial speed ,u = 0 m/s
We know that
v²=u²+2 g h
v=final speed
u=initial speed
h=height
Now by putting the values in the above equation
v² = 0²+ 2 x 10 x 4500
v²=90000
v= 300 m/s
Therefore the speed at sea level will be 300 m/s.
The solution for this problem:
The distance in mega parsec is equal to recession velocity / H, where h is equal to 50 mega parsec.The explanation for this is:1 parsec = 2.E+05 AU, nearly. 50 mega parsec = 1. E+13 AU, nearly. 1 mega means E+06 (million).
23) 560 cm
25) 3100 mg
27) 8.89 cm
29) 525 g
31) I can't see the measurement it needs to be converted to
Answer:
did you ever get the answer
