Explanation:
Below is an attachment containing the solution.
The bullet's vertical velocity at time 
is
where 
is the acceleration due to gravity.
At its highest point, the bullet's vertical velocity is 0, which happens
(or about 140 s, if you're keeping track of significant figures) after being fired.
We have equation of motion v = u + at
Where v = final velocity, u = initial velocity, a = acceleration, and t = time
In this case car is travelling in -x direction
Velocity of car = displacement / time
Since displacement value is increasing in negative x axis it's initial velocity is negative
And it's final velocity is zero since it comes to rest, and time is also positive
So, v= u+ at => 0 = -u + at
So, a = u/t
Which is positive and along positive X - direction
Answer:
difference in flight time= 0.3023 hour
Explanation:
The question is incomplete, but I found it in your textbook.
Spped of aircraft = 850 km/h
Opposing speed of wind = 90km/h
Hence, the net speed when it's travelling west = 850 - 90 = 760 km/hr
The distance covered = 1200km
time taken = distance/ time = 1200/ 760 = 1.5789 hours
When coming back, the speed of the wind is complementary to the speed of the aircraft so
net speed when it's coming back = 850 +90 = 940 km/hr
time taken in this instance = 1200/ 940 = 1.2765 hours
Hence, the difference in flight time= 1.5789 - 1.2765 = 0.3023 hour
