All categories

3 years ago

27 is 6 more than 3 times a number. What is the number.

Mathematics

2 answers:

Romashka-Z-Leto [24]3 years ago

5 0

27 = 6 + 3n
-6 -6
------------------
21 = 3n
-----------------
7 = n

wel3 years ago

3 0

Answer:

The required number is 7.

Step-by-step explanation:

It is required to find,

A number say 'x', such that, 27 is 6 more than 3 times the number.

That is, we have the relation, $3x+6=27$ .

On solving, we get,

$3x+6=27$

i.e. $3x=27-6$

i.e. $3x=21$

i.e. x = 7

So, the required number which hold the relation that '27 is 6 more than 3 times the number' is 7.

You might be interested in

Shawna drove set 264 miles in 5.5 hours at that rate how far can she drive in seven hours

Sindrei [870]

To do this divide set miles (264) by hours (5.5) to give you 48. Then multiply you mph (48) by 7. So in seven hours, Shawna can drive 336 miles.

4 0

3 years ago

The blue segment below is a diameter of 0. What is the length of the radius of the circle

Norma-Jean [14]

Answer:

Option (B) 5.1 units

Step-by-step explanation:

Since the radius of the circle is half of its diameter and given the diameter of the circle is 10.2 units then the radius would be $\frac{10.2}{2} = 5.1 units$

Thus the answer.

3 0

3 years ago

Read 2 more answers

Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

2 years ago

Simplify: (2x – 3)2 4x2 + 9 4x2 – 12x + 9 4x2 – 12x + 6 4x2 – 6

Alexxandr [17]

Answer:

$4x^2-12x+9$

Step-by-step explanation:

we have

$(2x-3)^2$

we know that

$(a-b)^2=a^2-2ab+b^2$

In this problem

$a=2x\\b=3$

substitute in the formula

$(2x-3)^2=(2x)^2-2(2x)(3)+(3)^2$

$(2x-3)^2=4x^2-12x+9$

7 0

2 years ago

Read 2 more answers

A graduated cylinder is used to measure the volume of a

vodomira [7]

C. Is the answer to your question

8 0

2 years ago