Answer:
C. 2(x + 10)(x - 10)
Step-by-step explanation:
Answer:
Minimum = 10
Q1 (quartile 1) = 14.5
Medium = 16
Q3 (quartile 3) = 17
Maximum = 18
Step-by-step explanation:
You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.
Tell me if I'm correct please
Step-by-step explanation:
Pathagory and Theorem
a^2+b^2=c^2
(x-3)^2+(x-4)^2=6^2
expand:
2x^2-14x+25=36
2x^2-14x-11=0
x=(\sqrt{71}+7)/2
perimeter=(x-3)+(x-4)+6=2x-1
insert the value for x into 2x-1
+6=perimeter
Hope that helps :)
Answer:
7 and 6 respectively
Step-by-step explanation:
Firstly, we have to solve the equations simultaneously.
2x + 7p = 56
3x - 11p = -45
Multiply equation I by 3 and ii by 2
6x +21p = 168
6x - 22p = -90
Subtract the second from first to yield:
43p = 258
p = 6
Insert this in equation 1 where we have 2x + 7p = 56
2x + 7(6) =56
2x + 42 = 56
2x = 14 and x = 7
The equilibrium price is 6 and the equilibrium quantity is 7
Answer:
A
Step-by-step explanation:
3 x r <u>></u> 34
