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Alenkasestr [34]
3 years ago
9

Please help me with this

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0
Answer is B. Bc it's 72/12 =.5
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Plz help
crimeas [40]

Answer:

-20/33

Step-by-step explanation:

y2 - y1 / x2 - x1

1/6 - (-1/4) / -5/16 - 3/8

5/12 / -11/16

= -20/33

8 0
2 years ago
Please help me on this question
Tasya [4]
I think Its C because in the frequency table or table given if the heads are counted there are 6 of them and over all 10 which will make 6/10
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3 years ago
Triangle AB is 15 BD 9 what is area ABC
krek1111 [17]

Answer:

it is your answer...... if it is helpful plzz like ans comment

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Fofino [41]

Answer:

Ok

Step-by-step explanation:

Do you like ice cream?

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5 0
3 years ago
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Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18

The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

Once more. Approximate f(x) at x_3.

f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

Then

\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

Compare this to the actual root of f(x), which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0
2 years ago
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