<span> i'm going to be slightly extra careful in showing each step. specific, ln [n / (n+a million) ]= ln n - ln(n+a million). So, we've sum(n=a million to infinity) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) ln [n / (n+a million) ] = lim(ok--> infinity) sum(n=a million to ok) [ln n - ln(n+a million)] = lim(ok--> infinity) (ln a million - ln 2) + (ln 2 - ln 3) + ... + (ln ok - ln(ok+a million)) = lim(ok--> infinity) (ln a million - ln(ok+a million)), for the reason that fairly much all the words cancel one yet another. Now, ln a million = 0 and lim(ok--> infinity) ln(ok+a million) is countless. So, the sum diverges to -infinity. IM NOT COMPLETELY SURE
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Answer:
x^8
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
I took the test
Step-by-step explanation:
Initial velocity(u) = 60 km/hr = 50/3 m/s
final velocity(v)= 0 (stops at rest)
acceleration(a) = -0.05 m/s²
display (s)=?
v²-u²=2as
0²- (50/3)= 2(-0.05)s
2500/9= 0.1s
s= 25000/9 m
Answer:
T= 2.35 seconds
Step-by-step explanation:
⇒The question is on the time of flight.
⇒Time of flight is the time taken for a projected object to reach the ground.It depends on the <u>projectile angle</u> and the <u>initial velocity</u> of the projectile
Given;
Initial velocity of ball= 110ft./sec.
The projectile angle= 20°
Acceleration due to gravity, g=32 ft./s²
⇒Formulae for time of fright T= (2×u×sin Ф)/g
Where T=time of fright, u=initial velocity of projectile, Ф=projectile angle and g=acceleration due o gravity.
<u>Substituting values</u>
T= (2×u×sin Ф)/g
T=( 2×110×sin 20°) / 32
T= 2.35 seconds