Question

Find the equation of the line which passes through the point

Answer 1

Answer:

$y= \frac{1}{5}x- \frac{56}{5}$

Step-by-step explanation:

We want to find the equation of the line that goes through: !6,-10) and is perpendicular to the line

$5x + 3y = 2y - 3$

Let's simplify the equation of the line to get:

$3y - 2y = - 5x + 3$

$y = - 5x + 3$

The slope of this line is -5.

The perpendicular to this line has a slope of

$\frac{1}{5}$

The equation going through (6,-10) is

$y=m(x-x_1)+y_1$

We substitute to get;

$y= \frac{1}{5} (x-6) - 10$

Expand;

$y= \frac{1}{5}x- \frac{6}{5} - 10$

$y= \frac{1}{5}x- \frac{56}{5}$