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g100num [7]
2 years ago
14

Find the equation of the line which passes through the point

Mathematics
1 answer:
sammy [17]2 years ago
7 0

Answer:

y= \frac{1}{5}x- \frac{56}{5}

Step-by-step explanation:

We want to find the equation of the line that goes through: !6,-10) and is perpendicular to the line

5x + 3y = 2y - 3

Let's simplify the equation of the line to get:

3y - 2y = - 5x + 3

y = - 5x + 3

The slope of this line is -5.

The perpendicular to this line has a slope of

\frac{1}{5}

The equation going through (6,-10) is

y=m(x-x_1)+y_1

We substitute to get;

y= \frac{1}{5} (x-6) - 10

Expand;

y= \frac{1}{5}x- \frac{6}{5}  - 10

y= \frac{1}{5}x- \frac{56}{5}

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The answer is division because u divide 3 from both side of the equation so that make the answer B
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What is a real world problem using mixed numbers who some is one and three
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Yesterday, Jake laid down 2/3 yards of duct tape on his tile floor. His friends wanted the line to be longer. Jake laid down 2/3 yards more duct tape. How long is the line of duct tape now?


8 0
3 years ago
24% of 75 is what number?
mariarad [96]
The answer is 18
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x/75 = 24/100
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6 0
2 years ago
Problem: How many cubic yards of concrete must be ordered to pour the section
timama [110]

Answer:

0.9 yd³

Step-by-step explanation:

Information given:

Length = 18 ft

Width = 1.5 ft

Height = 1 ft

What to find/do:

First, convert the measurement from feet to yards. (3 ft = 1 yard)

Length = 18 ft = 6 yd

Width = 1.5 ft = 0.5 yd

Height = 1 ft = 0.3 yd

Next, find the volume of the shape given. The volume would give us the amount of concrete to use in yards.

Formula for volume = L*W*H

Plug in the values into the formula

V = 6*0.5*0.3 = 0.9 yd³

0.9 cubic yard of concrete must be ordered to pour on the given section.

Area of the volume

4 0
3 years ago
A group of students weighs 500 US pennies. They find that the pennies have normally distributed weights with a mean of 3.1g and
inysia [295]
Question 1

probability between 2.8 and 3.3

The graph of the normal distribution is shown in the diagram below. We first need to standardise the value of X=2.8 and value X=3.3. Standardising X is just another word for finding z-score

z-score for X = 2.8
z= \frac{2.8-3.1}{0.41} =-0.73 (the negative answer shows the position of X = 2.8 on the left of mean which has z-score of 0)

z-score for X = 3.3 
z= \frac{3.3-3.1}{0.41}=0.49

The probability of the value between z=-0.73 and z=0.49 is given by 
P(Z<0.49) - P(Z<-0.73)

P(Z<0.49) = 0.9879
P(Z< -0.73) = 0.2327 (if you only have z-table that read to the left of positive value z, read the value of Z<0.73 then subtract answer from one)

A screenshot of z-table that allows reading of negative value is shown on the second diagram

P(Z<0.49) - P(Z<-0.73) = 0.9879 - 0.2327 = 0.7552 = 75.52%

Question 2
Probability between X=2.11 and X=3.5

z-score for X=2.11
z= \frac{2.11-3.1}{0.41}=-2.41

z-score for X=3.5
z= \frac{3.5-3.1}{0.41} =0.98

the probability of P(Z<-2.41) < z < P(Z<0.98) is given by
P(Z<0.98) - P(Z<-2.41) = 0.8365 - 0.0080 = 0.8285 = 82.85%

Question 3
Probability less than X=2.96

z-score of X=2.96
z= \frac{2.96-3.1}{0.41}=-0.34
P(Z<-0.34) = 0.3669 = 36.69%

Question 4
Probability more than X=3.4
z= \frac{3.4-3.1}{0.41}=0.73
P(Z>0.73) = 1 - P(Z<0.73) = 1-0.7673=0.2327 = 23.27%



7 0
3 years ago
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