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densk [106]
3 years ago
10

The work of a student trying to solve the equation 4(2x – 1) = 11 + 3x + 5 is shown below: Step 1: 4(2x – 1) = 11 + 3x + 5 Step

2: 8x – 4 = 16 + 3x Step 3: 8x + 3x = 16 – 4 Step 4: 11x = 24 Step 5: x = 2.18 In which step did the student first make an error and what is the correct step?
Mathematics
2 answers:
Alisiya [41]3 years ago
8 0
4(2x - 1) = 11 + 3x + 5

Step 1:  4(2x - 1) = 11 + 3x + 5

Well, this technically isn't really a step, but it's not incorrect.

Step 2 : 8x - 4 = 16 + 3x

This is correct, because we simplified, as well as added like terms together correctly.

Step 3 : 8x + 3x = 16 - 4

This is INCORRECT because when moving variables and integers from either side of the equal sign, you must change the sign! If it was a positive, then you must turn it into a negative, and if it's a negative, you must change it into a positive!

Our correct step 3 would be : 8x - 3x = 16 + 4

~Hope I helped!~


MatroZZZ [7]3 years ago
7 0
Step3 it suppose to be 8x-3x=16+4
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