Answer:
I will
Step-by-step explanation:
Thats yeah
Answer:
61 degrees
Step-by-step explanation:
==>Given ∆MNO,
MO = 18,
MN = 6
m<O = 17°
==>Required:
Measure of <N
==>SOLUTION:
Use the sine formula for finding measure of angles which is given as: Sine A/a = Sine B/b = Sine C/c
Where,
Sine A = 17°
a = 6
Sine B = N
b = 18
Thus,
sin(17)/6 = sin(N)/18
Cross multiply
sin(17)*18 = sin(N)*6
0.2924*18 = 6*sin(N)
5.2632 = 6*sin(N)
Divide both sides by 6
5.2632/6 = sin(N)
0.8772 = sin(N)
sin(N) = 0.8772
N = sin^-1(0.8772)
N ≈ 61° (approximated)
Answer: 46 years
Step-by-step explanation:
Let the father's age be x and the son's age be y, then 3 years ago:
Father = x - 3
son = y - 3
Then , from the first statement :
x - 3 = 3 ( y - 3 )
x - 3 = 3y - 9
x = 3y - 9 + 3
x = 3y - 6 .......................................... equation 1
In five years time
father = x + 5
son = y + 5
Then , from the second statement
x + 5 = 2 ( y + 5 )
x + 5 = 2y + 10
x = 2y + 10 - 5
x = 2y + 5 ........................ equation 2
Equating equation 1 and 2 , we have
3y -6 = 2y + 5
add 6 to both sides
3y = 2y + 5 + 6
subtract 2y from both sides
3y - 2y = 11
y = 11
substitute y = 11 into equation 1 to find the value of x
x = 3y - 6
x = 3(11) - 6
x = 33 - 6
x = 27
This means that the father is presently 27 years and the son is presently 11 years.
In four years time
father = 27 + 4 = 31
son = 11 + 4 = 15
sum of their ages in four years time will be
31 + 15 = 46 years
The top one is the answer
Answer:
the first option
Step-by-step explanation:
variability !
what does that word tell us ?
it means that there are more individuals differences.
you could also use "accuracy" as the opposite - we are aiming for the mean value ...
imagine some bow and arrow tournament.
who wins ?
the person with the highest accuracy across all the attempts (and that means the lowest variability in the results across all attempts relatively to the target center representing the predefined mean value).
now look at the graphic for neighborhood A.
and then for neighborhood B.
which one has the data points more clustered around the center (where the mean value is going to be) ? this one has lower variability than the one where the data points are having more than one cluster or are even all over the place.
remember, for the variability you have to add all the differences to the mean value. the smaller the differences to the mean value, the smaller the variability.
in neighborhood B almost all data points have a larger difference to the mean value.
so, the variability will be higher here.
